Homework Help for Algebra

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Tape a meter stick to the side of the table. Make sure the zero end is on the floor. Carry out the experiment using the four drop heights you chose in task 1, part D. (You may want to have an adult drop the ball while you watch how high it bounces.) Perform three trials for each drop height, and record the data in the table. (You may choose to video the bounces and watch the video in slow motion to improve your data collection.) Finally, average the bounce height measurements to get a final reading. Round the average bounce heights to the nearest whole number.

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per your answer:

Answer:

Step-by-step explanation:

To determine if there are any outliers in the data, we can use the interquartile range (IQR) method. The IQR is the difference between the third quartile (Q3) and the first quartile (Q1). To calculate the IQR, we first need to order the data from least to greatest.

$5, $40, $45, $50, $53, $55, $90, $155, $167

The median is the middle value, which is $53. The first quartile (Q1) is the median of the lower half of the data, which is $45. The third quartile (Q3) is the median of the upper half of the data, which is $90.

The IQR is then calculated as follows:

IQR = Q3 - Q1 = $90 - $45 = $45

An outlier is any value that is more than 1.5 IQRs below Q1 or above Q3. In this case, the lower outlier bound is Q1 - 1.5 * IQR = $45 - 1.5 * $45 = -$18.75. The upper outlier bound is Q3 + 1.5 * IQR = $90 + 1.5 * $45 = $180.

Therefore, any value less than -$18.75 or greater than $180 is considered an outlier. In this data set, there are two outliers: $5 and $167.

It is important to note that the IQR method is just one way to detect outliers. There are other methods that may be more appropriate for certain data sets.

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how is 167 an outlier it is less than 180

also how did you figure the lower and high Q1 & Q3?  I'm not coming up with the same #.  

$45 - 1.5 * $45

$90 + 1.5 * $45 = $180

Sally is driving in Radiator Springs and makes a sudden stop.  The drag factor of the road is 0.6 and the brakes are operating at 99% efficiency. 

If she leaves tire marks that are 40 and 46 feet long, how fast was she going?

Andie deposits $120 every month into a savings account that pays 3.3% interest compounded monthly.  

What is the balance after 12 years?

McQueen called 9 repair shops for quotes for auto repairs.  The prices are $90, $50, $45, $5, $167, $155, $40, $55, and $53.  

Use the outlier test to determine if there are any outliers in the data.

It seems there is a discrepancy in the calculation. Let's break it down:

1.The initial calculation you provided, PMT ≈ 200,000 / (0.111334/0.0020769), results in approximately $3,729.91 as the bi-weekly deposit to save $200,000 in 22 years with a 5.4% interest rate compounded bi-weekly.

2.However, when you multiplied $3,729.91 by 26 to represent one year's worth of deposits, you correctly calculated that it amounts to $96,977.66 per year.

3.Then, you multiplied this yearly amount by the total number of bi-weekly periods in 22 years, which is 572, and you calculated a total of $2,133,508.52.

So, the second calculation is indeed correct. To save $200,000 in 22 years with a 5.4% interest rate compounded bi-weekly, you would need to make bi-weekly deposits of approximately $3,729.91, and the total amount deposited over the 22-year period would be approximately $2,133,508.52. 

but the goal is only $200,000 not 2+ million