PHYS-1207EL Study Guide - Final Guide: Voltmeter

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31 Jan 2021

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Do not include this page in your report. You need to find the power of the headphone not the entire circuit. The circuit acts like the one you see below. You need to first find the value of current i1. Then you need to find the power at. Purpose: mmeeaassuurree tthhee oouuttppuutt ppoowweerr ooff hheeaaddpphhoonneess aanndd ccaallccuullaattee tthhee aauuddiioo ddbb lleevveellss aatt vvaarriioouuss ffrreeqquueenncciieess 11 aasssseemmbbllee tthhee cciirrccuuiitt aass sshhoowwnn iinn ffiirrsstt yyeeaarr pphhyyssiiccss llaabboorraattoorryy mmaannuuaall"" eexxppeerriimmeenntt. 22 sseett tthhee ssoouunndd ggeenneerraattoorr ttoo 550000 hhzz 33 sseett sswwiittcchh ttoo lleefftt oorr rriigghhtt eeaarr 44 aaddjjuusstt rreessiissttaannccee ttoo mmaaxxiimmuumm oonn ddeeccaaddee bbooxx 55 aaddjjuusstt aammpplliittuuddee oonn tthhee ggeenneerraattoorr uunnttiill 1155 vvoollttss iiss rreeaadd oonn vvoollttmmeetteerr 66 ssttaarrtt ddeeccrreemmeennttiinngg rreessiissttaannccee iinn sstteepp uunnttiill ssoouunndd iiss hheeaarrdd bbyy ppaattiieenntt tthheenn iinnccrreeaassee rreessiissttaannccee uupp oonnee sstteepp 77 ssttaarrtt iinnccrreeaassiinngg tthhee aammpplliittuuddee uunnttiill oonnee oorr bbootthh ppaattiieenntt((ss)) rraaiissee tthheeiirr hhaanndd rreeccoorrdd vvoollttaaggee aanndd rreessiissttaannccee sseettttiinngg ffoorr ffrreeqquueennccyy ffoorr tthhaatt ppeerrssoonn

Related Questions

Consider an L-R circuit as shown in the figure.Thebattery provides 12.0 V of voltage. The inductor hasinductanceL, and the resistor has resistanceR= 150 Î©. The switch is initiallyopen as shown. Attime t = 0, the switch is closed. At time t aftert = 0 the currentI(t) flows through the circuit as indicated in thefigure.

Part A:

What is the voltagechange V_r(t)across the resistor at time tafter t = 0?

What is the voltage changeV_ind(t)across the inductor at time t after t = 0? In thefollowingexpressions, ÎI/Ît denotes the time rate of change ofthecurrent in the inductor at time t?

After the switch is closed, thecurrentin the circuit grows over time approaching a constant value.Ingeneral, at time t after a voltage source is connected to anL-Rcircuit, the current I(t) in the circuit is given bytheexpression

I(t)=V/R(1-e^-t/Ï)

where V is the voltage provided bythebattery, R is the resistance of the resistor, and Ï is thetimeconstant characteristic of the circuit.

Part C:

What is the current I(Ï) flowing inthecircuit shown in the figure at one time constant after t =0?

Express your answer in amperes.

Hint: To find the current inthecircuit after one time constant, use the expression forI(t)given in the problem, with t equal to Ï. Do not try todeterminethe time constant for this circuit. You would not be ableto do sobecause the inductance L is unknown. Instead, afterplugging in thenumerical values for V and R appropriatefor this circuit andsubstituting Ï for time, simplifyyour expression to get a numericalvalue for the current.

You are given a circular conducting wire loop with one
end cut out and connected to a resistor, R, as shown in
the figure to the right. A metal rod of length l is set at an
initial angle ?0 from the resistor, and then rotates
clockwise about the center of the wire loop with angular
frequency through a uniform magnetic field B
directed into the page. The metal rod stays in contact
with the wire loop at all points of its motion. Unless
otherwise requested, all answers should be in simplified
algebraic form using the above given variables.

(a) Given that the initial angle ?0 is in radians, what is theinitial area of the closed circuit âwedgeâdefined by ?0? (2pts.)
(b) What is the magnetic flux through this initial âwedgeâ areadefined by ?0? (2 pts.)
Starting at time t=0 at position ?0, the rod is rotated clockwisewith angular velocity as shown in
the figure. Given this configuration, answer questions (c)-(g)below:
(c) What is the direction of the induced magnetic field inside theâwedgeâ? (2 pts)
(d) What is the direction of the induced current around the closedcircuit? (2 pts)
(e) What is the magnitude of the induced emf, E in the circuit? (4pts)
(f) What is the magnitude of the induced current in the circuit? (4pts)
(g) What is the power used by the resistor? (4 pts)
(h) The metal rod is now rotated in the opposite direction, i.e. inthe counter-clockwise direction. Given this information, completethe chart below as to what quantities you just calculated change,and what ones do not change. You do not have to show work, justgive the result. No partial credit will be given here. (5pts)

Direction of induced magnetic field inside the âwedgeâ.
Direction of the induced current around the closed circuit.
Magnitude of the induced emf, E in the circuit.
Magnitude of the induced current in the circuit.
Power used by the resistor.

The setup is now modified slightly so that the circular conductingwire loop no longer has a small
section removed as shown in both figures below. This modificationwould allow the metal rod to
continuously rotate on the circular wire loop as clearlyillustrated in the 3D side view. The metal rod
is rotated clockwise, as in the initial part of the problem.

(i) Given this information, complete the chart below. You do nothave to show work, just give the
result. No partial credit will be given here. (5 pts)

Direction of induced magnetic
field inside the âwedgeâ.
Direction of the induced current
around the closed circuit.
Magnitude of the induced emf, E in
the circuit.
Magnitude of the induced current
in the circuit.
Power used by the resistor.

A science museum has created ahuge concave mirror with a focal length of 5 m, and mounted it sothat it covers the entire wall at one end of a long hallway. If youstand on a center line painted down the middle of the hallway,you're on the mirror's principal axis. You and a friend arestanding on the center line, you're 8 m from the mirror, and yourfriend is 20 m from it. Can both you and your friend see the imageof you created by the mirror? Explain. (Don't worry about either ofyou blocking the other's line of sight â you both can crane yourheads as needed. The mirror is really, really big.)
.......................................................................................................

I TOOK A PIC OF THE ANSWER I TURNED IN
......................................................................................................
THE INSTRUCTORS RESPONSE WAS:
Very good. Please include units when giving your results. As forthe image being behind you, couldn't you just turn around to seeit?

You don't need to find where your friend's image is, just figureout whether he'd be able to see your image or not. How do you knowhe can see your image?

PHYS-1207EL Study Guide - Final Guide: Voltmeter

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