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in cats, black color is dominant to a special albino gene which produces cats with dark legs,faces, and tails,(Siamese cats). a short haired(dominant) Siamese colored short haired; 2 black, long-haired; 2 Siamese short haired; and 2 Siamese long haired, what were the genotypes of the two parents

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Related questions

6. In guinea pigs R-rough, r-smooth, S-short hair, s-long hair, B-black, b-white. A rough, long haired, black male is mated to a rough, short haired, white female. After they have produced several litters, their offspring are found to be as follows: 15 rough, short haired, black; 13 rough, long haired, black; 4 smooth, short haired, black; 4 smooth, long haired, black. What were the genotypes of the parents?

1. Short hair is due to a dominant gene (S) in rabbits and long hair is its recessive allele (s). A cross between a short-haired male and a long-haired male produced a litter of one long-haired and seven short-haired bunnies.

a) What ate the genotypes of the parents?

b) What phenotype ratio was expected on the offspring generation?

c) How many of the eight bunnies were expected to be long-haired?

2. The lack of pigmentation in humans called albinism is the result of a recessive gene and normal pigmentation if the result of its dominant allele. Two normal parents have an albino child. Determine the probability that the next child will be an albino.

Explain your answers.

I need to finish this by today. The dihybrid squares I can do butcan someone show me how to do this? I have no time :( care to help?please? (:

1. In guineaa pigs, long hair (L) is dominant to short hair (l).Black color (B) is dominant to albino (b). A heterozygous longhair, albino male is bred to a short haired black female. What arethe probable genotypic and phenotypic ratios of theiroffspring?

Well we have to make 2 dihybrid squares. And I have no idea how todo this..... :(

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