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Related questions

y'' + y = 6e^x

Here is my work so far:

Characteristic equation is (r^2+1). So general solution is: y =c1cosx + c2sinx + particular solution.

The annihilator I believe is (D-1). So (D^2 +1)(D-1)y = 0. Thus,(D^2+1)(Ae^x) = 6e^x.

Do some more work...

I arrive that A, the undetermined coefficient, is 2. Others findthat it is 3.

Who, if anyone, is right?

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