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6 Nov 2019
y'' + y = 6e^x
Here is my work so far:
Characteristic equation is (r^2+1). So general solution is: y =c1cosx + c2sinx + particular solution.
The annihilator I believe is (D-1). So (D^2 +1)(D-1)y = 0. Thus,(D^2+1)(Ae^x) = 6e^x.
Do some more work...
I arrive that A, the undetermined coefficient, is 2. Others findthat it is 3.
Who, if anyone, is right?
y'' + y = 6e^x
Here is my work so far:
Characteristic equation is (r^2+1). So general solution is: y =c1cosx + c2sinx + particular solution.
The annihilator I believe is (D-1). So (D^2 +1)(D-1)y = 0. Thus,(D^2+1)(Ae^x) = 6e^x.
Do some more work...
I arrive that A, the undetermined coefficient, is 2. Others findthat it is 3.
Who, if anyone, is right?
Here is my work so far:
Characteristic equation is (r^2+1). So general solution is: y =c1cosx + c2sinx + particular solution.
The annihilator I believe is (D-1). So (D^2 +1)(D-1)y = 0. Thus,(D^2+1)(Ae^x) = 6e^x.
Do some more work...
I arrive that A, the undetermined coefficient, is 2. Others findthat it is 3.
Who, if anyone, is right?
Tod ThielLv2
29 Sep 2019
