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If a particular liquid has a normal boiling point of 338.0 K, and a vapor pressure of 75.0 mmHg at 285.0 K, what is   (in kJ/mol) for the liquid?

Recall that 760 mmHg - 1 atm

Report your answer to 3 sig figs without units

I am pretty sure I have the correct change of heat invaporization... I am not positive on how to calculate the normalboiling point. Please advise.

please show work

Suppose you have two colorless molecular liquids, one boiling at –84 °C, the other at 34 °C, and both at atmospheric pressure. Which of the following statements is correct? For each statement that is not correct, modify the statement so that it is correct. (a) The higher-boiling liquid has greater total intermolecular forces than the lower-boiling liquid. (b) The lower-boiling liquid must consist of nonpolar molecules. (c) The lower-boiling liquid has a lower molecular weight than the higher-boiling liquid. (d) The two liquids have identical vapor pressures at their normal boiling points. (e) At –84 °C both liquids have vapor pressures of 760 mm Hg.