30 Dec 2021
Problem 63
Page 269
Section 4.2: Maximum and Minimum Values
Chapter 4: Applications of Differentiation
Textbook ExpertVerified Tutor
30 Dec 2021
Given information
Given function is
Step-by-step explanation
Step 1.
Since 
is measured in years since August of 1993 , the value of varies from 0 to 10 .
is measured in years since August of 1993 , the value of varies from 0 to 10 .Now, 
being continuous on the interval 
, we can use the Closed Interval Method:
being continuous on the interval , we can use the Closed Interval Method:
Since, 
exists for all , the only critical numbers of 
occur when 
. Thus we need to find the solution of the equation .
exists for all , the only critical numbers of occur when . Thus we need to find the solution of the equation .
Single Variable Calculus: Early Transcendentals
4th Edition, 2018
Stewart
ISBN: 9781337687805
Solutions
Chapter
Section
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