6 Jan 2022
Problem 51
Page 269
Section 4.2: Maximum and Minimum Values
Chapter 4: Applications of Differentiation
Textbook ExpertVerified Tutor
6 Jan 2022
Given information
The given integral and the interval is 
Step-by-step explanation
Step 1.
The given function 
is continuous on 
The value of 
at this critical numbers is
The value of at endpoints are
Comparing these numbers and using the Closed Interval Method, we see that the
The absolute minimum is
And the absolute maximum value is
Single Variable Calculus: Early Transcendentals
4th Edition, 2018
Stewart
ISBN: 9781337687805
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