Given information
9.5 percent of American adults suffer from depression or a depressive illness. In a survey of 100 adults in a town, 7 of them suffered from depression or depressive illness. A hypothesis test to determine if the true proportion of people in that town suffering from depression or a depressive illness is lower than the percent in the general adult American population is to be conducted.
From the previous task, the sample proportion is p'=0.07 while the hypothesized proportion is p=0.095. The sample size is n=100.
Step-by-step explanation
The random variable p represents the proportion of adults who suffer from depression or depressive illness. Since the sample size exceeds 100 and the number of successes (9.5% of 100=9.5) and failures (100-9.5=90.5) are both atleast 5, the normal approximation to the binomial distribution can be used to model the situation.
Unlock all Textbook Solutions
Introductory Statistics
Solutions
Chapter
Section
- Problem 62a
- Problem 62b
- Problem 62c
- Problem 62d
- Problem 62e
- Problem 62f
- Problem 62g
- Problem 62h
- Problem 62i
- Problem 62j
- Problem 63
- Problem 64
- Problem 65
- Problem 66a
- Problem 66b
- Problem 66c
- Problem 66d
- Problem 66e
- Problem 66f
- Problem 66g
- Problem 66h
- Problem 66i
- Problem 66j
- Problem 67a
- Problem 67b
- Problem 68
- Problem 69
- Problem 70
- Problem 71
- Problem 72
- Problem 73a
- Problem 73b
- Problem 73c
- Problem 73d
- Problem 73e
- Problem 73fi
- Problem 73fii
- Problem 73fiii
- Problem 73g
- Problem 73h
- Problem 73i
- Problem 73ji
- Problem 73jii
- Problem 73jiii
- Problem 74
- Problem 75
- Problem 76
- Problem 77
- Problem 78
- Problem 79
- Problem 80
- Problem 81
- Problem 82
- Problem 83
- Problem 84
- Problem 85
- Problem 86
- Problem 87
- Problem 88
- Problem 89
- Problem 90
- Problem 91
- Problem 92
- Problem 93
- Problem 94
- Problem 95
- Problem 96
- Problem 97
- Problem 98
- Problem 99
- Problem 100
- Problem 101
- Problem 102
- Problem 103
- Problem 104a
- Problem 104b
- Problem 104c
- Problem 104d
- Problem 105a
- Problem 105b
- Problem 105c
- Problem 105d
- Problem 106a
- Problem 107
- Problem 108
- Problem 109
- Problem 110
- Problem 111
- Problem 112
- Problem 113
- Problem 114
- Problem 115
- Problem 116