Textbook ExpertVerified Tutor
15 Nov 2021
Given information
the “Lap time” data for Lap 4=129; the sample size(n)=20; the degree of freedom (df)=20-1=19;
Step-by-step explanation
Step 1.
The sample mean for 132,129,127,125,132,129,131,130,128,132,131,130,128,131,129,128,131,130,129,128;
=(132+129+127+125+132+129+131+130+128+132+131+130+128+131+129+128+131+130+129+128)/20=129.5
The sample standard deviation(s);
(s)= (s)=2.124;
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