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23 Nov 2019
A 4.0 kg particle moves in an xy plane. At the instant when the particle's position and velocity are = (2.4 + 4.6) m and = -3.6 m/s, the force on the particle is = -3.1 N.Determine the following at this instant.(a) Find the particle's angular momentum about the origin.( 1 kg·m2/s)(b) Find the particle's angular momentum about the point x = 0, y = 4.6 m.( 2 kg·m2/s)(c) Find the torque acting on the particle about the origin.( 3 N·m)(d) the torque acting on the particle about the point x = 0, y = 4.6 m.( 4 N·m)
A 4.0 kg particle moves in an xy plane. At the instant when the particle's position and velocity are = (2.4 + 4.6) m and = -3.6 m/s, the force on the particle is = -3.1 N.Determine the following at this instant.(a) Find the particle's angular momentum about the origin.( 1 kg·m2/s)(b) Find the particle's angular momentum about the point x = 0, y = 4.6 m.( 2 kg·m2/s)(c) Find the torque acting on the particle about the origin.( 3 N·m)(d) the torque acting on the particle about the point x = 0, y = 4.6 m.( 4 N·m)
