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23 Nov 2019
A 3.0 kg particle with velocity v = (5.0 m/s) - (6.0 m/s) is at x =3.0 m, y = 8.0 m. It is pulled by a 7.0 N force in the negative xdirection.
(a) What is the angular momentum of the particle about theorigin?
kg·m2/s
(b) What torque about the origin acts on the particle?
N·m
(c) At what rate is the angular momentum of the particlechanging?
kg·m2/s2
A 3.0 kg particle with velocity v = (5.0 m/s) - (6.0 m/s) is at x =3.0 m, y = 8.0 m. It is pulled by a 7.0 N force in the negative xdirection.
(a) What is the angular momentum of the particle about theorigin?
kg·m2/s
(b) What torque about the origin acts on the particle?
N·m
(c) At what rate is the angular momentum of the particlechanging?
kg·m2/s2
Trinidad TremblayLv2
1 May 2019
