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9 Nov 2019



A 9.98 kg particle moves in an xy plane. At the instant when theparticle's position and velocity are = (2.00 + 5.00) m and = -6.39m/s, the force on the particle is = -1.22 N. At this instant,determine (c) the torque acting on the particle about the origin

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Bunny Greenfelder
Bunny GreenfelderLv2
28 Sep 2019
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Related textbook solutions

Physics: Principles with Applications
7th Edition, 2013
Giancoli
ISBN: 9780321625922

Related questions

At the instant of the figure, a 1.7 kg particle P has a positionvector r of magnitude 1.1 m and angle ?1 = 45° and a velocityvector v of magnitude 4.5 m/s and angle ?2 = 30°. Force F ofmagnitude 1.5 N and angle ?3 = 30° acts on P. All three vectors liein the xy plane.

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(b) What is the torque acting on the particle about theorigin?
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At the instant of the figure, a 1.7 kg particle P has a positionvector r of magnitude 1.1 m and angle ?1 = 45° and a velocityvector v of magnitude 4.5 m/s and angle ?2 = 30°. Force F ofmagnitude 1.5 N and angle ?3 = 30° acts on P. All three vectors liein the xy plane.

(a) What is the angular momentum of the particle about theorigin?
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