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2. You compare the amino acid sequences of an enzyme from yeast and human cells whose function is to break apart the disaccharide fructose. The amino acid sequences of these two enzymes are quite different. However, when you examine the 3-dimensional conformation of these two enzymes, you find that they have almost identical conformations. How is it possible for two proteins to have very different amino acid sequences and still fold the same way? (Hint: in your answer, consider the properties of the non-identical amino acids in the two enzymes). [6 points]

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27 Apr 2019
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Related questions

What is the percent sequence identity between hemoglobin (2HHB) and myoglobin (1A6M)?

A.

93%
B.

39.46%
C.

25.17%
D.

4.08%

QUESTION 2

Which of the following statements is consistent with the sequence similarity parameter?

A.

The abundance of amino acids with similar properties that are arranged in the same order is equal to the abundance of identical amino acids.
B.

These parameters are not related and cannot be compared.
C.

The abundance of amino acids with similar properties that are arranged in the same order is less than the abundance of identical amino acids.
D.

The abundance of amino acids with similar properties that are arranged in the same order is higher than the abundance of identical amino acids.

QUESTION 3

Which of the following statements is consistent with the similarity parameter and visualization of the aligned structures?

A.

Hemoglobin and myoglobin do not have similar structures.
B.

Hemoglobin and myoglobin have only moderately similar structures, as indicated by the large abundance of gray chains.
C.

Hemoglobin and myoglobin have very similar structures.
D.

Hemoglobin and myoglobin are perfectly aligned at every amino acid.

QUESTION 4

Hemoglobin (2HHB) is ___ amino acids shorter than myoglobin; the sequence alignment considers only ___ amino acids, and alignment results show that hemoglobin is missing a contiguous strand of ___ amino acids.

A.

10; 141; 6
B.

10; 141; 5
C.

10; 147; 6
D.

10; 147; 5

QUESTION 5

Which of the following statements best describes the evolutionary relationship between hemoglobin and myoglobin?

A.

The low sequence identity indicates that hemoglobin and myoglobin are not related, as tertiary structure cannot be used to study protein evolution.
B.

Both the high sequence identity and structural similarity suggest that hemoglobin and myoglobin are related.
C.

The difference in sequence identity and similarity values suggests that hemoglobin and myoglobin are related.
D.

The high structural similarity suggests that hemoglobin and myoglobin are related, while the low sequence identity suggests that the genes for each protein have diverged through mutation and deletion of several amino acids.

QUESTION 6

The comparison of sequences and tertiary structures in this exercise indicates that:

A.

only similar amino acid sequences can provide the same tertiary structure.
B.

different amino acid sequences can provide very similar tertiary structures.

QUESTION 7

The structures of deoxyhemoglobin and oxyhemoglobin are derived from the same source, have the same exact amino acid sequence and length, and differ only in the presence of noncovalently bound oxygen.

A.

True
B.

False

QUESTION 8

When using the Sequencing and Structure Alignment tool, the degree of the structural similarity is shown by the superimposition of the backbones. Accordingly, which of the following statement best describes the comparison of deoxyhemoglobin and oxyhemoglobin?

A.

Only slight differences in the backbone traces occur throughout the aligned proteins.
B.

The only differences in the backbone traces occur near the oxygen-binding sites.
C.

The backbone traces of the proteins are drastically different.
D.

The backbone traces of the proteins are identical.

QUESTION 9

The alignment of 2HHB and 1HHO shows that the binding of oxygen results in _______ in the protein.

A.

minor conformational changes at sites proximal and distal to the oxygen-binding site
B.

no conformational change
C.

drastic conformational changes
D.

minor conformational changes only within the oxygen-binding site

QUESTION 10

The alignment of 2HHB and 1HHO shows that the conformation of the Fe-heme group _____ upon oxygen binding.

A.

changes
B.

does not change

QUESTION 3

What is the purpose of chromatin-remodeling enzymes in human cells?

The enzymes control the rate of translation of an mRNA transcript

The enzymes add phosphate or methyl groups to histone tails

The enzymes slide nucleosomes farther apart or closer to each other

The enzymes send damaged proteins to the proteasome for degradation

The enzymes cause DNA looping to occur

QUESTION 10

If you can drink milk as an adult, it means that you have inherited a mutation in the an enhancer for your lactase gene (the gene that encodes the enzyme you need to break down lactose). Predict the effect of this mutation:

The mutation changes the number of domains in the enzyme, which makes it work more efficiently

The mutation changes the amino acid sequence of the lactase protein

The mutation increases the number of copies of the lactase gene that will be found in your genome

The mutation changes whether the lactase sequence is found in an intron or exon

The mutation affects the expression of the lactase gene

QUESTION 12

What determines where in the genome a transcription regulator will bind?

Transcription regulators bind to the 5' UTR region of a gene

Regulators bind via complementary base-pairing to certain DNA molecules

Covalent bonds form between the transcription regulator and the atoms of the DNA backbone

Every eukaryotic gene has a different transcription regulator that will bind to the 5' end of the gene

Transcription regulators bind to specific DNA sequences via multiple weak non-covalent interactions

QUESTION 15

What is the histone code used for?

Phosphorylation and acetylation of DNA affect its ability to be compacted

Changes to the sequence of DNA change whether DNA will wrap around histone proteins

Covalent modifications of histones affect the ability of the transcription initiation complex to form

Histones provide the codon sequences needed for translation to occur

The histone code affects which amino acids will get added to a polypeptide

5. Alpha amanitin is a drug that binds RNA polymerase andprevents it from functioning in the cell (this is the compound thatis found in poison mushrooms). The reason people die when theyconsume alpha amanitin is:

a) Alpha amanitin prevents gene expression from occurring in thecell

b) DNA replication is directly inhibited by alpha amantin

c) Alpha amanitin binds tightly to the messenger RNAs that aremade in the cell, preventing translation

d) Alpha amanitin binds to nuclear pores preventing thetransport of messenger RNA into the cytoplasm

6. In order for transcriptional initiation to begin in E. colithe following elements are needed:

a) an origin and RNA polymerase

b) initiator protein and a promoter

c) the sigma subunit of RNA polymerase and an RNA template

d) RNA polymerase and a promoter

e) helicase and primase

Questions 7 and 8. You are studying two species of closelyrelated snakes, one species lives in sandy desert area and has paletan skin and the species lives in a volcanic rock area and has darkbrown skin. You a sequence the DNA from each type of snake anddiscover a gene encoding a protein that transports pigment into theskin cells. The pigment transporter protein is responsible for skincolor. When you analyze the DNA coding sequence of the pigmenttransporter from each snake you find these two DNA sequences (hashmarks have been added to indicate the reading frame):

pale tan snake: GCG/TTG/GAC/TGC/ACC (DNA template strand)CGC/AAC/CTG/ACG/TGG (complementary strand) dark brown snake:ACG/TTG/GAC/TGC/ACC (DNA template strand) TGC/AAC/CTG/ACG/TGG(complementary strand)

7. From these sequences you conclude:

a) that the amino acid sequence of the pigment transporters forthe two proteins are almost identical

b) that the amino acid sequence of the pigment transporters forthe two proteins are very dissimilar

c) that the amino acid sequence of the pigment transporters forthe two proteins are identical

8. Since the skin color is different in each snake, you concludefrom the sequence data above that:

a) the genetic code in the skin cells in each of these snakes isdifferent

b) the DNA sequence encoding the entire gene for pigmenttransporters in these two snakes is different

c) that one of the codons in the gene for the pigmenttransporter in these two snakes is different

9. You are analyzing eukaryotic cells that have been exposed tothe radioactive uracil. In most cells the radioactive uracil isinitially localized in the nucleus and then moves from the nucleusto the cytoplasm. However, you observe that in some cells theradioactive molecules stay in the nucleus and never arrive in thecytoplasm. This is most likely a defect in:

a) the transcription of the DNA

b) the processing of the mRNA

c) the translation of the RNA

d) the labeling of the RNA

e) the replication of the DNA

10. Which of the following is true of both eukaryotic andbacterial transcription? (select all that are true)
a) Transcription factors must bind the promoter before RNApolymerase initiates transcription

b) Messenger RNAs must be spliced before translation begins inorder to produce the appropriate gene product

c) During transcription only one DNA strand is used as atemplate to make the messenger RNA

d) Termination of transcription occurs when the RNA polymerasetranscribes a hairpin structure in the RNA followed by a string ofU

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