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If a cell is placed in a cooler environment, the fluidity of the membrane can decrease. Would the cell increase the amount of saturated or unsaturated fatty acids in the phospholipid bilayer to restore the normal level of fluidity? Explain your answer.

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Deanna Hettinger
Deanna HettingerLv2
29 Sep 2019

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Related questions

1)(a) Saturated fatty acid tails have a different shape than unsaturated fatty acid tails. Briefly explain what this means in terms of chemical bonds.

(b) How does the difference in chemical bonds between saturated and unsaturated fatty acids affect the shape of these molecules.

(c) Cell membranes are made mostly of phospholipids (which contain fatty acids) that must maintain fluidity. What type of phospholipids would be better at maintaining fluidity: saturated phospholipids or unsaturated phospholipids? Explain your answer (and make sure your explanation relates to part b).

Select one answer.

How does the selective permeability of the membrane help thecell.

This allows the cell to maintain the proper shape.

This allows the cell to regulate what enters and exits

This allows the cell to maintain a constant temperature.

All of these

Question 6

Select one answer.

What is the role of carbohydrates in the plasma membrane?

cellular identification

adhesion

transport materials across the membrane

help maintain fluidity

Question 7

Select one answer.

Which component of the plasma membrane has the widest variety offunctions?

sterols

carbohydrates

phospholipids

proteins

Question 8

Select one answer.

All of the following have an effect on the fluidity of amembrane except:

interactions among fatty acids in the core of the bilayer

the cholesterol content

the ratio of saturated to unsaturated fatty acids

the presence of integral proteins in the membrane

The table below shows the percent of each type of phospholipid fatty acid tail found in each type of the grass membranes on Oct. 2 and Dec. 8th. The first column in the table shows the length of the fatty acid tail and the number of double-bonds in the fatty acid. For example the fatty acid รขย€ยœ16:0รขย€ย would be a fatty acid that was 16 carbons long and had 0 double-bonds. The second and third columns show the percent of all phospholipid fatty acids that were of this type. For example, in grass collected on October 2nd, 23.9 % of the phospholipid fatty acids were 16 carbons long and had no double-bonds (16:0 type), and in the grass collected on Dec. 8th, 21.0 % of the phospholipid fatty acids were 16 carbons long and had no double-bonds (16:0 type).

Fatty Acid composition

of Phospholipids

October 2

December 8

% of phospholipids

% of phospholipids

16:0

23.9

21.0

16.1

0.4

0.7

18:0

0.8

0.4

18:1

9.6

6.1

18:2

34.4

38.6

18:3

30.2

32.4

20:0

0.7

0.7

A. For each date the grass was collected, calculate the total percent of phospholipid fatty acids that were saturated fatty acids and the total percent of phospholipid fatty acids that were unsaturated fatty acids.

B. Draw a column graph that shows the total percent of phospholipid fatty acids that were saturated for each date that grass was collected and the total percent of phospholipids that were unsaturated for each date that grass were collected.

C. Why are the % of saturated and unsaturated fatty acid tails on the phospholipids of the Oct 2nd collected grass and the Dec 8th collected grass not the same? Use your understanding of membrane fluidity to address why these percentages have changed during this time period.

D. During this experiment the concentration of cholesterol found in the membranes of the grass was also measured. On Oct. 2th the concentration of cholesterol was 1.10 umol/mg and on Dec. 8th the concentration of cholesterol was 1.22 umol/mg. Why did the concentration of cholesterol change? Use your understanding of membrane fluidity to address why these concentrations have changed during this time period.

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