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URGENT - Due in an hour! Please help!

In our Bacterial Conjugation Experiment we will cross an Esherichia coli strain which has the plasmid pRL27 with a wild-type strain of Serratia marcescens. The plasmid pRL27 carries a gene for resistance to kanamycin on a transposable element that can be transferred to other strains of bacteria by conjugation. The E. coli donor strain is an auxotroph that requires diaminopimelic acid (DAP) as a growth factor.
We will use four types of agar media in this experiment.
MATCH the various types of media used in this experiment with the descriptions given below.

A L-agar + DAP
B L-agar + kan + DAP
C L-agar + kan
D

L-agar

Neither the wild-type Serratia marcescens nor the E. coli strain with the pRL27 plasmid can grow on this medium.
Both the wild-type Serratia marcescens and the E. coli strain with the pRL27 plasmid can grow on this medium.
The wild-type Serratia marcescens can grow on this medium, but the E. coli strain with the pRL27 plasmid can't.
The wild-type Serratia marcescens can't grow on this medium, but the E. coli strain with the pRL27 plasmid can.

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Nestor Rutherford
Nestor RutherfordLv2
28 Sep 2019

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Related questions

18) In your research on gene regulation in E. coli, you produce 2 mutant strains with the same phenotype: they can grow on lactose but not on glucose. To investigate these 2 mutants further, you perform a complementation test using them and discover that the diploid combination strain can grow on glucose or lactose. From this, you can deduce that:

a.)Both mutants have a mutation in the same gene

b.)The 2 mutants have mutations in different genes
c.)Glucose and lactose metabolic pathways in E. coli utilize at least one shared gene in common
d.)At least 2 different genes are required for glucose metabolism in E. coli
e.) b) and d)

19. In your research on the lac operon, you produce a unique regulatory mutatant strain of E. Coli where the lac l gene's repressor protein binding site for the operator is normal (wild-type) but its lactose binding site no longer binds lactose. The expected phenotype of this mutant will be:

a. inability to grow on lactose only medium

b. ability to grow on lactose only medium

c. blue colony color when grown on glycerol plus x-gal medium

d. blue colony oclor when grown on lactose plus x-gal medium

e. b & d

20.

20) In your research on the lac operon, you create a diploid E.coli strain with the following genotype (+) = wild type gene, (-) = mutant gene.

I- /O+ /Z- /Y+

I+ /Oc /Z+ /Y+
Can this diploid mutant grow on medium containing lactose as the only carbon source?

a) Yes

b) No

c) Maybe, it depends on if the Oc mutation is dominant or recessive

Hfr Mapping Problem

An Hfr E. coli contains the following genetic traits: kans, lac+ , his+ , trp+ , ampr . It is mated with a recipient E. coli that contains the opposite genetic traits for those traits listed abov: kanr. lac- , his- , trp- , amps . Assume all other catabolic and biosynthetic genes are present in both strains. Note that kanS means the absence of the kanamycin resistance gene in the Hfr strain, which will allow growth only of the recipient cells in the presence of kanamycin. This is necessary to select against the Hfr donor strain as you are monitoring which genes transferred to the recipient.

At periodic intervals, conjugation is disrupted and cells are plated onto several types of defined media. Nothing grows at the beginning of the experiment on media containing lactose, kanamycin, and ampicillin as this is the most selective medium, but all cells grow on complex media containing no ampicillin (the least selective medium). Mating is interrupted at the times listed below and the following are some of your observations of growth characteristics on a few of the selective media plates containing the indicated nutrients/antibiotics:

15 min.

Growth on defined media containing: kanamycin, glucose, histidine (does not contain tryptophan).

No growth on defined media containing: kanamycin, lactose (sole carbon source), tryptophan, histidine.

30 min.

Growth on defined media containing: kanamycin, lactose (sole carbon source), histidine (does not contain tryptophan).

No growth on defined media containing: kanamycin, glucose, tryptophan (does not contain histidine).

No growth on defined media containing: kanamycin, ampicillin, lactose (sole carbon source), histidine, tryptophan.

45 min.

Growth on defined media containing: kanamycin, lactose (sole carbon source) (does not contain histidine or tryptophan).

No growth on defined media containing: kanamycin, ampicillin, lactose (sole carbon source), histidine (does not contain tryptophan).

60 min.

Growth on defined media containing: kanamycin, lactose (sole carbon source) (does not contain histidine or tryptophan).

No growth on defined media containing : kanamycin, ampicillin, lactose (sole carbon source) (does not contain histidine or tryptophan).

Multiply questions here

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