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In Drosophila, the gene for bar-shaped (B) eyes and the gene for scalloped wings (sc) are linked on the X-chromosome. (The normal or wild type eye shape is oval, and the wild type wing is rounded.) Heterozygous, bar-eyed females were mated to homozygous, scalloped-wing males. The offspring are as follows:

phenotype female male
scallop 183 186
bar 189 188
wild type 12 10
scallop & bar 9 12

-What is the map distance between the two genes?

-Give the exact phenotypes of the F1 flies.

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Deanna Hettinger
Deanna HettingerLv2
28 Sep 2019

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