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Hemophilia is an X-linked recessive trait in humans. Consider amale with hemophilia, he has children with a female who does nothave hemophilia, but her father did have hemophilia. Create aPunnett square to show their genotypes, their gametes, and thepotential genotypes of their children. Since it is X-linked, youneed to show the alleles on the X and Y chromosomes, so useXH for normal allele, Xh for hemophiliaallele, and Y.

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Sixta Kovacek
Sixta KovacekLv2
28 Sep 2019
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Related questions

In humans, hemophilia is a sex linked trait. Females can be normal, carriers, or have the disease. Males will either have the disease or not (but they won’t ever be carriers)

X H X H = female, normal / X H Y = male, normal

X H X h = female, carrier

X h X h = female, hemophiliac / X h Y= male, hemophiliac

Show the cross of a man who has hemophilia with a woman who is a carrier. What is the probability that their children will have the disease? __________

7. A woman who is a carrier marries a normal man. Show the cross. What is the probability that their children will have hemophilia? What sex will a child in the family with hemophilia be?

8. A woman who has hemophilia marries a normal man. How many of their children will have hemophilia, and what is their sex?

1. If you had a fruitfly with phenotype A, what test would you make to determine if it was Aa or AA? Explain the different outcomes expected if the fly in question is AA or Aa.

2.The sex of birds, some insects, and other organisms is determined by a ZW chromosomal arrangement in which the males have like sex chromosomes (ZZ) and females are ZW (similar to XY in humans). Assume that a recessive lethal allele on the Z chromosome causes death of an embryo in birds. What sex ratio would result in the offspring if a cross were made between a male heterozygous for the lethal allele and a normal female?

3.A recessive gene for red-green color blindness is located on the X chromosome in humans. Assume that a woman with normal vision (her father is color-blind) marries a color-blind male. What is the likelihood that this couple's first son will be color-blind?

4. One form of hemophilia is caused by a sex-linked recessive gene. Assume that a man with hemophilia marries a phenotypically normal woman whose father had hemophilia. What is the probability that they will have a daughter with hemophilia? (Note: In this problem, you must include the probability of having a daughter in your computation of the final probability.)

5. One form of hemophilia is caused by a sex-linked recessive gene. Assume that a man with hemophilia marries a phenotypically normal woman whose father had hemophilia. What is the probability that their first son will have hemophilia?

1. (8 points) Anhydrotic ectodermal dysplasia is an X-linked recessive disease in cattle, causing tooth abnormalities and hairlessness. Arachnomelia is an autosomal recessive condition that causes spider legs in newborn calves. Use ‘D’ to indicate the dominant, normal teeth and hair in cattle and ‘d’ for the dysplasia. Use ‘L’ for normal legs and ‘l’ for spider legs. Suppose a heifer having normal teeth and hair and normal legs but whose sire had dysplasia and spider legs is backcrossed to her sire.

a. What are their genotypes?

b. What are the genotypes, phenotypes, and genotypic and phenotypic proportions we expect in their progeny?

2. (6 points) In German Shepherds, hemophilia A is an X-linked recessive disease, affecting the blood clotting times in dogs having the disease. Use ‘+’ to indicate the normal, normal blood clotting time allele and ‘a’ for the hemophilia allele. A bitch (female) who has normal blood clotting times and whose sire (male) had hemophilia A is mated with a sire with normal blood clotting times but whose sire also had hemophilia A.

a. What are the genotypes of the 4 dogs described in the problem?

b. What are the genotypes, phenotypes, genotypic and phenotypic proportions you would expect to observe in the puppies produced from this cross?

3. (8 points) In turkeys, inhibited feathering is a sex-linked dominant gene (F). Use ‘f’ to denote the normal feathering allele. Suppose a bald hen (female) is crossed with a normally feathered rooster.

a. What are the genotypes of the two birds described?
b. What are the genotypes, phenotypes, genotypic and phenotypic proportions expected in the F1 progeny? c. What will be the genotypes, phenotypes and proportions produced when the F1 males are backcrossed?

4. (8 points) In guinea pigs, short hair (H) is dominant to long hair (h) and the heterozygous condition when you cross a yellow coat (CY) and white coat (CW) gives you a cream coat. These two loci are located on different chromosomes. A heterozygous short-haired cream guinea pig is crossed to a long-haired white guinea pig.

a. What are the genotypes, phenotypes and proportions of the pups (baby guinea pigs) produced?

b. What are the genotypes, phenotypes and proportions expected if we crossed the heterozygous short- haired cream guinea pig with a heterozygous short-haired yellow guinea pig?

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