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30 Sep 2018

Cell line I which has a mutation that prevents its lac repressor from ever binding DNA. Cell line II has a mutation that prevents its CAP from ever binding DNA. The expression level of beta-galactosidase in the mutated cell lines will equal the maximum possible expression in the unmutated cell line when:

A. There is glucose in cell line I and no glucose in cell line II.

B. There is lactose in cell line I and no glucose in cell line II.

C. There is lactose and no glucose in cell lines I and II.

D. There is no glucose in cell line I. It will never happen for cell line II.

E. There is glucose in cell line II. It will not happen for cell line I.

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Collen VonLv2

1 Oct 2018

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Related questions

Given the following mutants and conditions, predict the expression level of the of the lac Z gene. Please indicate your answer with one of followings: no expression, basal level of expression, or activated level of expression. Explain why, in the context of activities by activator and repressor:

I. A mutant of E.coli that has a mutation in the repressor gene (Lac I) for regulating lac operon

a. In the presence of glucose, presence of lactose

b. In the presence of glucose, absence of lactose-

c. In the absence of glucose, absence of lactose-

d. In absence of glucose, presence of lactose-

II. A mutant of E.coli that has a mutation in the cAMP binding site of CAP

a. In the presence of glucose, presence of lactose â

b. In the presence of glucose, absence of lactose â

c. In the absence of glucose, absence of lactose â

d. In absence of glucose, presence of lactose -

amaranthsquirrel358

Cell Biology (#1-5)

1) What does a non-synonymous DNA mutation cause?

a) No amino acid change

b) A change in the reading frame of the mRNA

c) The substitution of an amino acid

d) Creates a premature termination codon

e) All of the above

2) What does a non-sense DNA mutation cause?

a) No amino acid change b) Alters the normal reading frame of the mRNA

c) The substitution of an amino acid

d) Creates a premature termination codon

e) All of the above

3) If you sequence the genome of 100 cells from different tissues of the same multicellular organism. How do you expect the sequences to be?

a) 10% identical c)100% identical

b) 50% identical d) 100% different e) will depend on the tissue selected

4) Multicellular organisms are comprised of a variety of cells with different morphologies and different functions. Which is the underlying mechanism that leads to the generation of diverse cell in one organism?

a) The expression of all genes in all cell types

b) The duplication of the genome in certain cell types

c) The elimination of specific group of genes from different cell types

d) The differential expression of particular sets of genes requires for a particular cellular phenotype

e) All of the above

5)You are growing bacteria which can use lactose and glucose. The culture medium has lactose, which induces transcription of the enzymes required to use lactose. If you add glucose to the medium. What do you expect to happen?

a) The bacteria will keep using lactose

b) The bacteria will shut down the Lac operon and use glucose

c) The bacteria will stop growing

d) The bacteria will die

e) The bacteria will use both lactose and glucose