L24 Math 233 Lecture Notes - Lecture 27: Glossary Of Arithmetic And Diophantine Geometry, Iterated Integral, Nissan L Engine
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L24 Math 233 Lecture 26: L24 Math 233 Lecture 26- Iterated Integrals
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L24 Math 233 Lecture Notes - Lecture 27: Glossary Of Arithmetic And Diophantine Geometry, Iterated Integral, Nissan L Engine
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L24 Math 233 Lecture Notes - Lecture 28: Cartesian Coordinate System, Multiple Integral, Iterated Integral
Document Summary
L24 math 233 lecture 27- iterated integrals and different types domains. This is an iterated integral and represents the volume under the graph (x, )da y f. Find the volume of a tetrahedron bounded by. Idea: find a height function f on base region d, then compute. Two different ways of looking at f: x + 2 + z = 2 y x = 2 y, x = 0 = 0. Choose xy form of d since height function is simpler. Note: we"re using x to parametrize because d is type i. Then, volume equals the iterated integral with those characteristics. { y : 0 x 1 g (x, ) Y g2 } y = 1 2. = [ 3 x3 x2 + x 1. D2 f (x, )da y (x, )da y. This graph is not type i or type ii, but it can be made to be.
