CHE 131 Lecture Notes - Lecture 9: Molar Mass, Solution, Molar Concentration

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It is important to differentiate between solute and solvent. A combination of solute and solvent makes a solution. Solutes can range from things such as salts and molecular compounds. Solvents can range from things such as water and organic compounds. Define the amount of solute in a solution. You can do this by either: amount of solute/amount of solvent, amount of solute/amount of solution the common concentration units are either mass of solute and moles of solute. This is equivalent to (mg solute/kg solvent) Useful for very small amounts of solute. The less commonly used unit would be ppb = parts per billion = (1g/10^9 g). stony brook university, che 131. M = n/v and therefore, n=mv and also v=n/m. Che 131 lecture 9 solution concentration, dilutions. M = moles of sulute (n) / volume of solution (l) M= (grams of solute)/(molar mass of solute) / liter of solution. For small concentrations use milli or micro molarity.

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