STAT 1051 Lecture Notes - Lecture 17: Quartile, Miraculin, Binomial Distribution
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Suppose x is normally distributed random variable with u=50 and =3, find the value. Example: of the random variable, call it x0 such that: p(x. ) = 0. 8412 x 50 (cid:1248) z (cid:1248) 3. Mean = 105. 3 and standard deviation is 8. 0. X = the amount of miraculin produced (cid:1248) z (cid:1248) 1. Find a such that p(x a) = 0. 25. From the table, p((0 z 0. 67) = 0. 2486 (cid:1248) (cid:1248) = 105. 3 - a = ( 8 x 0. 67 ) = 5. 36. Suppose x is a binomial random variable with a large n. Note that z = 0. 67 of the upper quartile and the z = -0. 67 is the lower quartile. When you want to check a binomial distribution you can use the interquartile range. The histogram for a distribution of x is bell shaped. N is large with np and nq both greater than or equal to 5. Here p = p(success) and q = 1 - p.
