STAT 1051 Lecture Notes - Lecture 16: Cumulative Distribution Function, Standard Score, Papist

• School: GWU
• Department: Statistics
• Course: STAT 1051
• Professor: Balaji, S

Document Summary

Stat 1051 lecture 13 chapter 5: normal distribution (october 17, 2018) = 0. 3849: p(0 (cid:1248) z (cid:1248) 1, p(-2. 1 z 2. 1) (cid:1248) (cid:1248) = p(0 z 1) + p(0 z 2. 36) = 0. 3413 + 0. 4909 = 0. 8322 (cid:1248) (cid:1248) = 0. 0869 (cid:1248) (cid:1248) (cid:1248) (cid:1248: p(-1 z 2. 36, p(z -2)(cid:1248) 0. 5 - 0. 4772= 0. 0228: p(1 z 2) (cid:1248) (cid:1248) Z a u (cid:1248) x u (cid:1248) (cid:1248: p(x. Suppose x is normally distributed with mean u=4 and = 2. = p(2 3) = 0. 5 - p(0 z 3) = 0. 5 - 0. 4987 = 0. 0013 (cid:1248) (cid:1248: p(2 x 6) (cid:1248) (cid:1248) For all these problems you use the normal distribution table . Normal distribution table: distribution function(based on z scores) Median is z=0 z score you use. Table for the values of , which are the values of the cumulative.