MA129 Lecture 4: Review
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3 x2 x 2 = ( x2 x 2 = 3x2 6 3 + 6 x x2 x 2 = 3x2 9 + 6. 0 = 3x2 x2 9 + x + 6 + 2 x. But due to a restriction, =x / 2. X+1 ( x + 1 2 = 2 2 2 (x x + 1 = 2 2 2. 0 = 2x2 x 2 1. 1 requires x + 1 0 requires x + 1 > 0. Rules: a < b a + c < b + c a < b c c a < b > 0 a > b c c a < b < 0 then then. Proof: (dr. allison) a < b a < b c < 0 a b < 0. We can label this (1) and will give you. Since the product of two negative numbers results in a positive number, then (1) gives you: a ( b.
