MTH 162 Final: MTH 162 University of Rochester Fall 16Finalsol

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31 Jan 2019
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Part a: (15 points) evaluate the integral. 4 x2 dx = z 8 cos3 . 3 (cid:19) + c ( 4 x2)3 sin3 . Using the shell method we have shells of radius x, thickness dx and height (x3 + 1) 1 = x3. 5 (cid:12)(cid:12)(cid:12)(cid:12) (b) set up the integral for the volume of the region bounded by y = x4, y = 0 and x = 2 and rotated around line x = 2. Using the shell method we have shells of radius (2 x), thickness dx and height x4. Integrating by parts with u = arcsin x and dv = dx, we get du = dx. 1 x2 and v = x, so that the integral becomes. Z arcsin x dx = x arcsin x z x dx. Now make the substitution w = 1 x2, so dw = 2x dx and x dx = dw/2. Math 162 (calculus iia) and the original integral is.

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