MTH 162 Midterm: MTH 162 University of Rochester Fall 15Exam1 Solutions2

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31 Jan 2019
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October 15, 2015: (20 points) (a) use integration by parts to express in =r /2. Answer: cosn x dx in terms of in . Let u = cosn v = sin x. Use sin2 x = 1 cos2 x to get. 1x and dv = cos x dx, so du = (n 1) cosn . We have and therefore cosn x dx = uv(cid:12)(cid:12)(cid:12) = (n 1)z /2 cosn x dx = (n 1)z /2 cosn . 2 x dx (n 1)z /2. 2 x sin2 x dx cosn x dx. nz /2. 0 (b) use the formula of part (a) repeatedly to nd i6. You will not get partial credit here if the formula you are using is incorrect. A tank has the shape of an inverted pyramid (point down) with a square base. 8 ft tall and the area of its base is 16 ft2. The tank is lled with uid to a height of 2 ft.

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