MTH 162 Midterm: MTH 162 University of Rochester Fall 10Exam1 Solutions

14 views7 pages
31 Jan 2019
Department
Course
Professor

Document Summary

October 19, 2010: (20 points) evaluate the following integrals: (a) (10 points) (b) (10 points) B (x 2)(x + 2)(x2 + 4) A(x + 2)(x2 + 4) + b(x 2)(x2 + 4) + (cx + d)(x2 4) By comparing numerators we must have a + b + c = 0, 2a 2b + d = 0, 4a + 4b 4c = 0 and 8a 8b 4d = 48. From this we get a = 3/2, b = 3/2, c = 0 and d = 6. 2 z dx x + 2 6z dx x2 + 4. The rst two integrals are done by substitution, u = x 2 in the rst integral and u = x + 2 in the second integral. Therefore we use substitution u = x/2 and 2du = dx, then the last integral is. = 3 tan 1 u = 3 tan 1(x/2) .

Get access

Grade+20% off
$8 USD/m$10 USD/m
Billed $96 USD annually
Grade+
Homework Help
Study Guides
Textbook Solutions
Class Notes
Textbook Notes
Booster Class
40 Verified Answers

Related Documents

Related Questions