MTH 162 Midterm: MTH 162 University of Rochester Fall 11Exam1sol

10 views8 pages
31 Jan 2019
Department
Course
Professor

Document Summary

October 18, 2011: (20 points) evaluate the following integrals: (a) (10 points) 3x (x + 1)(x3 + 1) dx. (b) (10 points) 3x (x + 1)(x3 + 1) (x + 1)2(x2 x + 1) By comparing numerators we must have a + c = 0, b + 2c + d = 0, b + c + 2d = 3 and a + b + d = 0. From this we get a = c = 0, b = 1 and d = 1. Alternatively, we can use heaviside"s method to nd the constants. Multiply both sides of (1) by (x + 1)2 and get. = a(x + 1) + b + (x + 1)2 cx + d x2 x + 1. Subtracting the b term from both sides of (1) gives. 3x + x2 x + 1 (x + 1)2(x2 x + 1) x2 + 2x + 1 (x + 1)2(x2 x + 1)

Get access

Grade+
$40 USD/m
Billed monthly
Grade+
Homework Help
Study Guides
Textbook Solutions
Class Notes
Textbook Notes
Booster Class
10 Verified Answers

Related Documents

Related Questions