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PHGY 212 Study Guide - Final Guide: Resting Potential, Nernst Equation, Goldman Equation

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graywolf744
25 Sep 2017
School
McGill University
Department
Physiology
Course
PHGY 212
Professor
Melissa Vollrath

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Document Summary

It is a function of: ratio of ion [c] in cell and ecf, permeability of membrane to these ions, relevant ions: na+, k+, cl- Ionic asymmetry and selective membrane permeability lead inevitably to a rmp. Ionic asymmetry: k+ high in cell and low in ecf, na+ high in ecf and low in ecf. If [c] across both sides is equal, the force of the gradient would be zero, and eq potential would be zero. Thus, increase in [c] gradient = increase in eq potential: the equilbirum potential for any ion can be calculated using the nernst equation, ek=58log10 ([k+]o=ecf/[k]i=icf, ek is a function of [c] ratio only. Idea: at rest, the muscle membrane is permeable only to k+. If this is so, the resting membrane potential should be equal to the eq potential ek. A graph of ek to vs. log10 [k+]o should be linear with slope=58.

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Related Questions

Cell membranes contain openings called ion channels that allow ions to move from the inside of the cell to the outside. Consider an ion channel with a diameter of 0.6 nm and a length of 14 nm with R = 109 O. During an action potential, this channel is open for approximately 1.0 ms for the flow of Na+ ions with a potential difference across the cell membrane of about 65 mV. How many Na+ ions travel through the channel?

Cell membranes contain openings called ion channels that allow ionsto move from the inside of the cell to the outside. Consider an ionchannel with a diameter of 0.6 nm and a length of 14 nm with R =109 O. During an action potential, this channel is open forapproximately 1.0 ms for the flow of Na+ ions with a potentialdifference across the cell membrane of about 65 mV. How many Na+ions travel through the channel?