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Triple some in array

  1. We will discuss the multiple approaches to solve this problem and finally we will write its Java code. The easiest approach is to use three loops to solve the problem. The expected time complexity is 1 square without using any extra space. The brute force approach is the simplest approach or you can say the brute force approach. The time complexity is bigger of and cube so basically we are using three four loops right and it 's a space complexity is big o of 1 as we are not using any extra space right. After that, basically we return the value true. If the array is sorted we do n't have to make all possible sets right, we can do the sum of the three numbers and accordingly move the pointers so let me explain this so we have given this array right. First, let's sort this array and then use two pointers to solve the problem.

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