Question

Problem 46a

Answer 1

Given information

There are two capacitors with capacitance   and  . The capacitors are in series along with a battery of 9V. It is required to get the voltage drop across each capacitor when they are in series.

 

Step-by-step explanation

Step 1.

It is known that, the relationship between voltage drop(V) and charge stored(Q) for capacitor C is,

          (i)

 

To get the total charge stored in the circuit, first we need to get the total capacitance of the circuit.

 

If C is the equivalent capacitance for capacitor   and   which are in series. Then,

 

Therefore, charge stored in the circuit is,

 

As and are in series, therefore charge on both capacitors is 3.33 µC.