12 Nov 2021
Problem 15
Page 253
Section: Problems
Chapter 9: Static Equilibrium; Elasticity And Fracture
Textbook ExpertVerified Tutor
12 Nov 2021
Given information
We are given that:-
The force 
is applied at a distance of 
from the pivot.
is applied at a distance of from the pivot.The force required to pull the cork out of the top the range of 
to 
.
to .Step-by-step explanation
Step 1.
The bottle opener will pull upward on the cork with a force of magnitude 
, so there is a downward force on the opener of magnitude .
, so there is a downward force on the opener of magnitude .We assume that there is no net torque on the opener, so it has no angular acceleration. Calculate torques about the rim of the bottle where the opener is resting on the rim.
Formula used:
The net torque,
Here, 
is the applied force and 
represents its corresponding distance from the rotational axis.
is the applied force and represents its corresponding distance from the rotational axis.
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Physics: Principles with Applications
7th Edition, 2013
Giancoli
ISBN: 9780321625922
Solutions
Chapter
Section
- Problem 1
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