A single strand of bacterial DNA contains the base sequence:

5â CGT GTA TTC ACA CTG GTG AGC CAC TAT CGT ATA TTC CCT GAG TGA GCA TTG 3â

A. What is the complementary sequence? Write this sequence below with its polarity.

B. Write the 6 reading frames below (group nucleotides in codon, i.e. ACGCVGTG â¦ = ACG CVG TG. ...) ?

C. Is there an open reading frame (ORF) at least 4 codons long? If yes, what is the reading frame (+1,+2,+3, -1,-2 or -3) for the ORF?

D. Does the strand of the DNA given in (a) serve as the coding strand or template strand for the synthesis of the RNA transcript?

answer

watching

318

views

For unlimited access to Homework Help, a Homework+ subscription is required.

You have 0 free answers left.
Get unlimited access to 3.8 million step-by-step answers.

Get unlimited access

Already have an account? Log in

Elin HesselLv2

11 Nov 2018

Unlock all answers

Get 1 free homework help answer.

Already have an account? Log in

Related questions

A. Please identify the mRNA and polypeptide sequence for the below DNA using the genetic codon table. (Note: the direction of mRNA is important! Keep in mind that the genetic codons are read from 5â to 3â direction on mRNA. Also, RNA bases are A, U, C, G instead of A, T, C, G)

3â â GTT â TAC â CTT â CTC â TCC â TCA â GAC â ATC â GCA â 5â (Template strand)

5â â CAA â ATG â GAA âGAG â AGG â AGT âCTG â TAG â CGT â 3â (Non-template/Coding strand)

B. Please identify the mutation type (silent, missense, nonsense, frameshift) on the following DNA sequence as compared to the original sequence from question A.

3â â GTT â TAC â CTT â CTC â TTC â TCA â GAC â ATC â GCA â 5â (Template strand) 5â â CAA â ATG â GAA âGAG â AAG âAGT â CTG â TAG â CGT â 3â(Non-template/Coding strand)

C. Please identify the mutation type (silent, missense, nonsense, frameshift) on the following DNA sequence as compared to the original sequence from question A.

3â â GTT â TAC â CTT â ATC â TCC â TCA â GAC â ATC â GCA â 5â (Template strand)

5â â CAA â ATG â GAA âTAG â AGG â AGT â CTG â TAG â CGT â 3â(Non-template/Coding strand)

Can someone please check and help me with these? Especially II and III?

I. Below is a DNA sequence that is a template strand and contains an Open reading frame for a gene:

3â TAA ATA CGT GAG GCA CTT CAA AGA CCG CAC ACT_ AAT TT 5â

5â AUU UAU GCA CUC CGU GAA GUU UCU GGC GUG UGA _ UUA AA 3â

a. Transcribe the DNA template into a strand of mRNA by typing the mRNA sequence below the template strand. Label the 5â and 3â end of the mRNA 5â AUU UAU GCA CUC CGU GAA GUU UCU GGC GUG UGA _ UUA AA 3â

b. Paste the mRNA below and do all 3 reading frames. Highlight all start codons green in all the reading frames. Highlight red the stop codons which are in frame with the start codons in all the 3 reading frames if they are present.

1) 5â AUU UAU GCA CUC CGU GAA GUU UCU GGC GUG UGA UUA AA 3â

2) 5â A UUU AUG CAC UCC GUG AAG UUU CUG GCG UGU GAU UAA A 3â

3) 5â AU UUA UGC ACU CCG UGA AGU UUC UGG CGU GUG AUU AAA 3â

c) In which reading frame is the ORF found? The second one. Since it has AUG.

d) Paste the mRNA showing the most likely ORF below and translate the codons. Label the 5â and 3â end of the mRNA and the N- and C-termini of the peptide.

5â A UUU AUG CAC UCC GUG AAG UUU CUG GCG UGU GAU UAA A 3â

MET HIS SER VAL LYS PHE LEU ARG CYS ASP STOP

N Terminus C Terminus

II. 3 pts. The base calling program made a mistake that you didnât catch and deleted the bolded G in the original template strand above. Paste the template DNA below and delete the G. Transcribe (show the codons) and translate the resulting sequence. Label the 5â and 3â ends of the DNA and mRNA and the N and C-termini of the peptide. Comment on the resulting peptide sequence.

5â AUUU AUG CAC UCC GUG AAG UUU CUG GCG UGU GAU UAA A â3

MET HIS SER VAL LYS PHE LEU ARG CYS ASP STOP

III. 3 pts. The base calling program made a mistake that you didnât catch and added an extra G after the bolded G in the original template strand above. Paste the template DNA below and insert the extra G. Transcribe (show the codons) and translate the resulting sequence. Label the 5â and 3â ends of the DNA and mRNA and the N and C-termini of the peptide. Comment on the resulting peptide sequence.

5â AUUU AUG CAC UCC GUG AAG UUU CUG GGG UGU GAU UAA A â3

MET HIS SER VAL LYS PHE LEU GLY CYS ASP STOP