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Did you find that the two ears of corn followed the Principle of Segregation? Did the purple and yellow kernels occur in Mendelian ratios, or not? Explain your answer and any reason you feel the ratios may/may not have deviated from the predicted results.

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Deanna Hettinger
Deanna HettingerLv2
29 Sep 2019

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Related questions

1. In Drosophila (fruit flies) ebony body color and being eyeless are both autosomal recessive traits. An ebony fly is mated with an eyeless fly and the F1 are all wild type.

The F2 are: 590 wild type

185 eyeless

200 ebony

72 eyeless and ebony

Test the hypothesis that this was a dihybrid cross (ratios) using the Chi Square test.

2. In corn, purple kernels are dominant over yellow kernels, and full kernels are dominant over shrunken kernels.

A plant with purple, full kernels is crossed with a plant having yellow, shrunken kernels and the following progeny are obtained:

Purple, full 115

Purple, shrunken 110

Yellow, full 95

Yellow, shrunken 94

Determine the most likely genotypes for the parents and progeny.

Test your genetic hypothesis (ratios) with a Chi Square test until it is accepted.

3. A corn plant with purple, full kernels is crossed with a plant having purple, full kernels. The following progeny are obtained:

Purple, full 100

Purple, shrunken 36

Yellow, full 30

Yellow, shrunken 8

Determine the genotypes of the parents and progeny.

Test your hypothesis with a Chi square test until it is accepted.

4. A candy manufacturer claims that it puts equal numbers of different colored candy in each packet they sell. You buy a packet and find these results:

Red: 101 Green: 120 Blue: 133 Orange: 103 Yellow: 110 Brown: 153

Does the manufacturer’s claim hold true? Use the Chi square test to determine whether to accept or reject this claim (that each bag has the same number of each color of candy).

These all relate to exceptions to the inheritance patterns encountered by Mendel.​

Why do multiple and lethal alleles often result in modifications of the classic Mendelian monohybrid and dihybrid ratios?

Select the four correct statements.

-When an essential gene is mutated, it can result in a lethal phenotype. There are no classic Mendelian monohybrid and dihybrid ratios.
-In the case of codominance, heterozygotes produce gene products from both alleles of a gene. Classic Mendelian monohybrid and dihybrid ratios are modified by codominance.
-In the case of incomplete dominance, the phenotype of the heterozygote is distinct from and often intermediate to the phenotypes of homozygous individuals. Classic Mendelian monohybrid and dihybrid ratios are modified by incomplete dominance.
-Genes exist in a large number of allelic versions and a diploid organism has two homologous gene loci that may be occupied by different alleles of the same gene. This can result in many different phenotypes for traits, which may not follow typical Mendelian ratios.
-When an essential gene is mutated, it can result in a lethal phenotype. This results in a modification of classic Mendelian ratios.
-The phenotype of the heterozygous genotype is distinct from and often intermediate to the phenotypes of the homozygous genotypes. The joint expression of both alleles in a heterozygote is called codominance. There are no classic Mendelian monohybrid and dihybrid ratios.
-Genes exist in a large number of allelic versions, but in a diploid organism, only one allele of the gene can occupy one homologous gene loci. Classic Mendelian inheritance cannot explain this phenomenon.
-Each gene produces a unique gene product. The effect of one allele in a heterozygote completely masks the effect of the other. Classic Mendelian genetics cannot explain this phenomenon.

Suppose you have two species of corn. One has sweet kernels and the other has large ears. Both have 20 chromosomes, each of which is homologous in both species. Suppose you want to create a hybrid that has both characteristics of sweet kernels and large ears, so you cross individuals from the two species. The initial hybrid you obtain has 20 chromosomes, but then you establish a viable tetraploid (4n) individual with 40 chromosomes. Which of the following could best explain this observation?

Nondisjunction of a single chromosome caused the doubling of the genome.

The initial F1 hybrid was unable to produce normal haploid gametes and instead produced diploid gametes. As a result, self-fertilization created progeny with 40 chromosomes.

The original F1 hybrid was able to produce normal gametes, thus, the tetraploid was formed by fusing one normal haploid gametes with an abnormal diploid gamete.

Nondisjunction of a random set of chromosomes produced abnormal gametes, and thus the 40 chromosomes represent a random assortment of chromosomes from the two parents.

None of the above can explain the phenomenon.

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