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A heterozygous woman carrying the recessive gene for color blindness marries a man who is color-blind. Assume the dominant gene is XC (allele for normal color vision) and the recessive gene is Xc (determines color blindness). The mother’s genotype is XCXc and the father’s XcY. Do a Punnett square to determine the answers to the following questions.According to the laws of probability, what percentage of all their children will be color-blind? __________ % What is the percentage of color-blind individuals by sex? __________% males; __________% females What percentage of all children will be carriers? __________%What is the sex of the carriers? __________________. A heterozygous woman carrying the recessive gene for hemophilia marries a man who is not a hemophiliac. Assume the dominant gene is XH and the recessive gene is Xh. The woman’s genotype is XHXh and her husband’s genotype is XHY. What is the potential percentage and sex of their offspring who will be hemophiliacs? __________% males; __________% females What percentage can be expected to lack the allele for hemophilia?__________% What is the anticipated sex and percentage of individuals who will be carriers for hemophilia? __________%; __________sex

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Tod Thiel
Tod ThielLv2
28 Sep 2019

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