Question:
If a female animal with genotype A/A. b/b (the back-slash indicates the chromosome) is crossed with a male that is genotypically a/a. B/B and the F1 is testcrossed, determine the percentage of the progeny from the testcross that will be a/a. b/b, if the two genes are:
a. Unlinked (Show your work).
Answer: AaBb X aabb AaBb â ¼ aabb - ¼ aaBb - ¼ Aabb - ¼ OK
b. Completely linked, i.e., no crossing over at all (Show your work).
Answer: With completely linked genes without crossing over, the only genes possible are AB and ab gametes.
Result:
Therefore the only possibility of having homozygous aabb is 50%.
No; a b is recombinant; please redo
c. 10 mp units apart (Show your work).
Answer: If the linked genes are 10 map units apart, 10% of the results would be recombinants. As F1 progeny ab is part of the parental class, only half of the total parental genotypes will be present. Therefore: 45%
No; a b is recombinant; please redo
d. 24 map units apart (Show your work).
Answer: Same rule applies for c. Therefore the percentage of progeny would be equal to 38%.
No; a b is recombinant; please redo
This is all the information given and need help. I've answered the question and my prof says the answers for b c and d are wrong. Could you please help me out? and also could you explain with the answers? Thank you.
Question:
If a female animal with genotype A/A. b/b (the back-slash indicates the chromosome) is crossed with a male that is genotypically a/a. B/B and the F1 is testcrossed, determine the percentage of the progeny from the testcross that will be a/a. b/b, if the two genes are:
a. Unlinked (Show your work).
Answer: AaBb X aabb AaBb â ¼ aabb - ¼ aaBb - ¼ Aabb - ¼ OK
b. Completely linked, i.e., no crossing over at all (Show your work).
Answer: With completely linked genes without crossing over, the only genes possible are AB and ab gametes.
Result:
Therefore the only possibility of having homozygous aabb is 50%.
No; a b is recombinant; please redo
c. 10 mp units apart (Show your work).
Answer: If the linked genes are 10 map units apart, 10% of the results would be recombinants. As F1 progeny ab is part of the parental class, only half of the total parental genotypes will be present. Therefore: 45%
No; a b is recombinant; please redo
d. 24 map units apart (Show your work).
Answer: Same rule applies for c. Therefore the percentage of progeny would be equal to 38%.
No; a b is recombinant; please redo
This is all the information given and need help. I've answered the question and my prof says the answers for b c and d are wrong. Could you please help me out? and also could you explain with the answers? Thank you.
Related textbook solutions
Related questions
Question 3 (6 pts). In hogs, colored hair (H) is completely dominant to colorless (h) and bent tails (B) are completely dominant to straight tails (b). There are no interlocus interactions. Penetrance and expressivity are 100%. The two loci are not sex-linked. The phenotypes and frequencies of progeny following testcrosses of hogs 1 and 2 to a double recessive genotype (hh bb) are listed in the table:
| Phenotype | Testcross Progeny of hog 1 | Testcross Progeny of hog 2 |
| colored, bent | 134 | 28 |
| colored, straight | 11 | 335 |
| colorless, bent | 12 | 358 |
| colorless, straight | 143 | 30 |
| TOTALS | 300 | 751 |
For testcross progeny of hog 1, what are the recombinant classes or recombinant phenotypes in the progeny?
For testcross progeny of hog 2, what are parental classes or parental phenotypes in the progeny?
For hog 2, are the recessive alleles in the cis or trans configuration?
(2 pts) How far apart (in cM) are the two gene loci on the genetic map? You can use data from progeny of hog 1 or hog 2. Show your work.
For hog 1, If the two loci were sorting or segregating independently, what fraction of the testcross progeny would you expect to have colored hair and straight tails
