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Chromatographic assay reveals that the total amount of T3 in the blood is 10 μg. You find that the various bound forms of the hormone are:

T3(free) = 0.5%

T3 ~ albumin = 12 %

T3~TBG = 69 %

and T3~pro-albumin = 18.5 %

Target tissue: heart whose Bmax of T3 receptors = 76 fmol of T3 receptor/mg protein (1 fmol = 10-15 mol), where you have 100 μg protein (total protein of which T3 receptors makes only a tiny fraction) in your heart assay. MW = 68 kDal = 68,000 g/mol [Dasmalopatra et al., Receptor, 2(4):213-223, 1992]. This reference is only for the MW of T3 receptor, and not for the solution to this question. Note: You won’t need the MW of T3 because you already have the amount in g.

This is another conceptual question. So, don’t get all caught up in equations. In fact, don’t use the equations I provided in lecture, 6MemR. If you had freshman chemistry or physics (and all of you should have), then you can solve the following:

Calculate the amount (in g) of available T3 and its receptor (also in g). How do the 2 amounts compare? Will Bmax be reached (10 points)?

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Nestor Rutherford
Nestor RutherfordLv2
28 Sep 2019

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