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30 Sep 2018

Phenotype
Purple
Red
Yellow
White

Observed #
175
57
52
16

Observed ratio
9.3
3.0
2.8
0.9

Mendelian Ratio
9
3
3
1

How did they arrive at the mendelian ratio? If crosses are used to get the mendelian ratio. Please explain in FULL DETAIL!!! HELP NEEDED!!!!!!!

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Related questions

In this study you will learn about a modification of Mendelian inheritance which is also an important source of genetic variation.

You are about to perform what looks like a classic dihybrid testcross ("A" is the gene for eye color and "B" is the gene for wing color.)

A allele for red eyes

a allele for white eyes

B allele for clear wings

b allele for spotted wings

(AaBb) X (aabb) Note the genotypes and phenotypes.

Question #1: Predict the expected phenotypic ratio of this P X P cross.

Observed results:

500 red eyes clear wings

500 white eyes spotted wings

Question #2: How do the expected results compare with the observed results?

Question #3: Considering Mendel's second law (regarding dihybrid crosses), suggest an explanation for the discrepancy between the observed results and those predicted.

Genes are located at specific positions on a chromosome. The distance between genes is measured in terms of "mapping units". In this exercise the gene for wing phenotype “B” will be moved from its original position of zero to different positions on the chromosome. You will observe the effect of this gene movement.

First, gene "B" (wing color) is moved from position zero to position 10 on the same chromosome. Gene "A" (eye color) stays at position 0.

Observed Results: (position 10)

450 red eyes clear wings

50 red eyes spotted wings

50 white eyes clear wings

450 white eyes spotted wings

Question #4: How do these results differ from those predicted by Mendel's second law?

Question #5: From those in the first cross?

Question #6: Can you suggest a hypothesis to explain these new results?

Gene "B" (wing color) is now moved to position 20 on the same chromosome. Gene "A" (eye color) stays at position 0.

Observed Results: (position 20)

400 red eyes clear wings

100 red eyes spotted wings

100 white eyes clear wings

400 white eyes spotted wings

Question #7: How do the proportions of the phenotypic classes in this cross differ from the proportions you obtained in the earlier crosses?

The wing color gene "B" is now moved farther away (positions 30, 40, 50, and 60).

Observed Results: (position 30)

350 red eyes clear wings

150 red eyes spotted wings

150 white eyes clear wings

350 white eyes spotted wings

Observed Results: (position 40)

292 red eyes clear wings

220 red eyes spotted wings

195 white eyes clear wings

293 white eyes spotted wings

Observed Results: (position 50)

250 red eyes clear wings

250 red eyes spotted wings

250 white eyes clear wings

250 white eyes spotted wings

Observed Results: (position 60)

250 red eyes clear wings

250 red eyes spotted wings

250 white eyes clear wings

250 white eyes spotted wings

Question #8: Prepare a line graph plotting the % of recombinant offspring (Y-axis) vs. difference in position between the two genes (X-axis). (Hint: your graph should be one line with labeled points at map positions 0, 10, 20, 30, 40, 50, & 60).

Question #9: A genetic definition of "1 map unit" is the distance between 2 genes that gives 1% recombinants out of the total number of progeny. Using this definition, how many map units separate the "A" and "B" genes when the eye color gene "A" is at position 0 and the wing color gene "B" is at position 40? (Show how you determined the results.)

Question #10: How does the distance between two genes on the same chromosome affect the proportion of recombinants? Why?

Question #11: Maximum crossover frequency can be defined as the point at which no more recombination can be detected no matter how far apart the genes are located. Do your results indicate that you are approaching the maximum crossover frequency?

Question #12: Show (using a Punnett Square) the expected phenotypic rations if the two genes were located on different chromosomes.

Question #13: Which of your simulated cross or crosses do the data from the Punnett Square most closely fit? Why?

Question #14: A wild-type fly (heterozygous for gray body color and normal wings - b+ vg+/b vg) was mated to a black fly with vestigial wings (b vg/b vg). The F1 had the following phenotypic distribution: wild type, 850; black body - vestigial wings, 899; black body - normal wings, 79; gray body - vestigial wings, 85. What is the recombination frequency (RF) between these genes for body color and wing type? (show work)

Question #15: A cross produced 915 offspring with normal pigment and 310 with albinism. Conclusion?

a. One of the parents was homozygous for albinism.

b. Both parents were heterozygous.

c. One parent was homozygous for normal pigmentation.

d. Both parents were albinos. e. 605 albino zygotes must have failed to develop.

NOTE: Please show all work to support your answers.

Question 1 Select one answer.

Two heterozygous individuals are crossed. What percentage oftheir offspring will be heterozygous?

a)50%

b)75%

c)100%

d)25%

Question 2 Select one answer.

In peas purple is dominant to white for flower color. A purpleflower is crossed with a white flower. All the offspring (over 100plants) produce purple flowers. What is the genotype of the purpleflower?

a)pp

b)Either PP or Pp

c)PP

d)Pp

Question 3 Select one answer.

A heterozygous germ cell undergoes meiosis. The gametes will

a)only have the recessive allele

b)only have the dominant allele

c)either have the dominant or the recessive allele

d)have both the dominant or the recessive allele

Question 4 Select one answer.

Sex-linked disorders

a)are always dominant are

b)always recessive

c)can be either dominant or recessive

d)are neither dominant nor recessive

Question 5 Select one answer.

A nucleus is built around chromatids which have separated. Thisoccurs during which stage of meiosis?

a)Telophase II

b)Metaphase I

c)Metaphase II

d)Telophase I

Question 6 Select one answer.

The condition of having anincorrect number of chromosomes is called ____________.

a)nondisjunction

b)aneuploidy

c)epistatis

d)trisomy

Question 7 Select oneanswer.

In humans females are

a)XY

b)YY

c)none of these

d)XX

Question 8 Select oneanswer.

Autosomal means that the gene isfound on the

a)X chromosomes

b)the Y chromosome

c)either the X or the Ychromosome

d)neither on the X nor theY

Question 9 Select oneanswer.

What organism did Mendelstudy?

a)Roses

b)Ants

c)Peas

d)Yeast

Question 10 Select oneanswer.

Huntington's disease is anautosomal dominant disorder. If two individuals who areheterozygous at this locus breed, what are the chances that theiroffspring will develop Huntington's?

a)100%

b)75%

c)50%

d)25%

Question 11 Select oneanswer.

Plum gametes have 24 chromosomes.How many chromosomes would a zygote have?

a)12

b)24

c)36

d)48

Question 12 Select oneanswer.

Hydrangeas are blue in acidicsoil with available aluminum, and they are pink in alkaline soilwithout available aluminum, but they cannot be orange under anysoil condition. The color of hydrangeas is affect by

a)genetics only

b)the environment only

c)genetics and theenvironment

Question 13 Select oneanswer.

Somatic mosquito cells have 6chromosomes. How many chromosomes do gametes have?

a)3

b)6

c)12

d)24

Question 14 Select oneanswer.

Alleles are different versions ofa

a)Gene

b)Phenotype

c)Genotype

d)Chromosome

Question 15 Select oneanswer.

A female producesgametes:

a)that have either an X or a Ychromosome

b)That have 2 Xchromosomes

c)that have a Y chromosomeonly

d)that have an X chromosomeonly

Question 16:

use the following infromation to answer the next 4 questions

In dogs, colored fur (E) is dominant to un-colored fur (e).Blackfur color (B) is dominant to brown fur color (b). The E gene isepistatic to the B gene. A yellow male dog is mated to a blackfemale. the male's parents were both brown dogs. The female'smother was yellow and her father was brown

Q1 of 4: what is the genetype of the male dog in thisexample

a)eeBb

b)eeBB

c)ee

d)eebb

Q2 of 4: What is the genotype of the female dog in thisexample?

a)EeBb

b)EEBB

c)EeBB

d)EEBb

Q3 or 4: What percentage of their puppies will be yellow?

a)100%

b)75%

c)50%

d)25%

Q4 of 4: what percentahe of the puppies will be homozygous forthe B gene.

a)100%

b)75%

c)50%

d)25%

This experiment is about Affinity Purification of Green Fluorescent Protein (GFP)

please answer the below questions

1. What is a bacterial colony?

2. Why did you pick one green colony and one white colony from your agar plate(s)? Why do you think you picked one of each color? What could this prove?

3. How are these items helpful in this cloning experiment? a. ultraviolet (UV) light - b. incubator - c. shaking incubator

4. Explain how placing cloned cells in nutrient broth to multiply relates to your overall goal of purifying the fluorescent protein.

5. You have used a bacterium to propagate a gene that produces a green fluorescent protein. Identify the function of these items you need in this procedure. a. Centrifuge – b. Lysozyme – c. Freezer –

6. Can you explain why both liquid cultures fluoresce green?

7. Why did you discard the supernatant in this part of the protein purification procedure?

8. Can you explain why the bacterial cells’ outer membrane ruptures when the cells are frozen. What happens to an unopened soft drink when it freezes?

9. What was the purpose of rupturing or lysing the bacteria?

10. Briefly describe hydrophobic interaction chromatography and identify its purpose in this lab.

This lab is about Crystal Growth of Hen Egg White Lysozyme so please answer the following question

1. What condition yielded the "best" crystals of lysozyme?

2. What changes did your group try to make, and what effect did they have on the crystals?

3. How many of your conditions yielded crystals? How many did the entire class get? Give the percentage (number of conditions that gave crystals/number of different conditions that were set up) for your attempts as well as for the entire class. What does this tell you about protein crystallization?

4. What methods can you think of to determine if the crystals are lysozyme and not salt (many salt crystals are colorless as well)? (Hint: think of protein properties and ways to assay and look at proteins).

5. Many protein crystals are formed at or near the pI of the protein being studied. Can you rationalize any reason why this observation might be made (in other words, why is the pI so good at helping form protein crystals).

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