CHEM 1A Lecture Notes - Lecture 24: Stoichiometry, Equivalence Point, Sodium Hydroxide

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CHEM 1A Full Course Notes
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Chem 1a - lecture 24 - titration and buffers. Acetate ion produced by the neutralization becomes a part of the available acetate: Hc2h3o2(aq) + oh (aq) (cid:12206) c2h3o2(aq) + h2o(l) 40 ml di water + 2 ml 1. 0m naoh. 40 ml buffer solution + 2 ml 1. 0 m naoh. Step 1: let reaction, h+ with a or oh with ha, go to completion. Determine new concentrations of ha and a . Determine the ph of a solution when we mix 40. 0 ml 1. 0 m hcl and 30. 0 ml 1. 0 m. The endpoint and the equivalence points are not always the same. Titrate 25. 0 ml of 1. 0 m ch3cooh with 1. 0 m naoh. For 1. 0 m ch3cooh: initially ph = 2. 4. Draw the graph: ph vs volume of naoh added. Write the net ionic equation for the reaction that occurs during the titration: a) ch3cooh + na+ + oh- b) ch3cooh + oh c) ch3cooh + naoh .

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