CHEM 1127Q Lecture Notes - Lecture 14: Oxidation State

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Reference (dr. wasalathanthri, lecture 14-ch. 3, slide 32) them separately. 1. assign oxidation numbers for all the elements. 2. separate the oxidation half reaction and reduction half reaction and balance. 3. balance all elements except oxygen and hydrogen. If necessary, multiply each half-reaction"s coefficients by the smallest possible. Add the balanced half-reactions together and simplify by removing species integers to yield equal numbers of electrons in each that appear on both sides of the equation. Problem reference ( dr. wasalathanthri, lecture 14-ch. 3, slide 33) ) , its oxidation number has increased (aq. Balance the oxidation half reaction : . If you multiply the equation by 2, we get . ***you do this because you need to yield equal numbers of electrons in each*** 6 is a common multiple of 3 and 2*** If you multiply the equation by 3, we get. *** as you can see, both half-reactions are balanced , and yield the same number of electrons ***

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