Physics 1028 Study Guide - Final Guide: Virtual Image, Lisa Lopes, Curved Mirror
Document Summary
Solution to part (a): we know from table 22. 1 that both the radius of curvature r and the focal length f are positive for a concave mirror. Thus, we know that the focal length f = r/2 = 10. 0 cm. We answer the question for each of the three cases using the mirror equation (eq. [22. 3]) and the equation for the magnification for a mirror (eq. For p = 10. 0 cm we find: which yields q = 4. This means that there is no image formed; the light rays are reflected in the mirror such that they travel parallel to each other. Solution to part (b): for p = 20. 0 cm we get: (1) which yields for q: and the magnification is: (2) (3) (4) Thus, the image is formed 20 cm in front of the mirror; it is real and inverted and of the same size as the object.
