1
answer
0
watching
236
views
26 Nov 2019
An object is held 99.5 cm away from a mirror. The mirror hasafocal length of 72.9 cm.
a.) Determine the image distance.
1 cm
b.) Determine the magnification.
2
c.) If the object is 9.8 cm long, determine the image height.
3 cm
d.)Which of the following are true about the image? Choose allthatapply.
4
The image is virtual.
The image is upright.
The image is inverted.
The image is real.
a) The image distance
q =pf / p -f = 99.5*72.9 / 99.6-72.9 =272.69 cm
(b) Magnification m = -q/p = -272.69 / 99.5 = - 2.74
(c) magnification m = hf / hi
-2.74 = hf / 9.8
hf = -26.85 cm
(d) for lens image is real and inverted
An object is held 99.5 cm away from a mirror. The mirror hasafocal length of 72.9 cm.
a.) Determine the image distance.
1 cm
b.) Determine the magnification.
2
c.) If the object is 9.8 cm long, determine the image height.
3 cm
d.)Which of the following are true about the image? Choose allthatapply.
4
The image is virtual.
The image is upright.
The image is inverted.
The image is real.
a) The image distance
q =pf / p -f = 99.5*72.9 / 99.6-72.9 =272.69 cm
(b) Magnification m = -q/p = -272.69 / 99.5 = - 2.74
(c) magnification m = hf / hi
-2.74 = hf / 9.8
hf = -26.85 cm
(d) for lens image is real and inverted
Hubert KochLv2
9 Apr 2019
