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BIOL462 Study Guide - Midterm Guide: Aeration

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taupellama672
20 Apr 2014
School
University of Waterloo
Department
Biology
Course
BIOL462
Professor
Barry Warner

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Document Summary

E 6: d f w s o d (h s o r n t w l a d m. M), s l/h c m s, g y, r d e, v. S d: g n m l e. M, l l l, n: p s s: 3 t. S i t o n o f n (cid:224) t o n s l d d e p s: e/p r a e d a. R e f e o i a p v a i l a b l o s b o u n d a r i e s (cid:224) U s u a l l e s o l v u e s t i o n i s p u t e s (cid:224) S m: f t s/m s: s/s r m g o n e, t s s r, a s, s r s, i s o c d i.

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Related Questions

For each of the E. coli strains below, determine the effect ofthe genotype on expression of the trpE and trpC genes in thepresence and absence of tryptophan. In the wild-type strain(genotype: R+ P+ O+ att+ trpE+ trpC+), the trpE and trpC genes arefully induced in the absence of tryptophan and fully repressed inthe presence of tryptophan.

Key:

R = functional repressor gene; Rn = product cannot bind tryptophan;R- = product cannot bind operator

O = functional operator; O- = operator cannot bind repressorprotein

att = functional attenuator; att- = a deletion of the attenuatorsequence

P = functional promoter; P- = a deletion of the trp operonpromoter

trpE- and trpC- = produce non-functional protein products

1) R+ P- O+ att+ trpE+ trpC+

2) R- P+ O+ att+ trpE+ trpC+

3) Rn P+ O+ att+ trpE+ trpC+

4) R- P+ O+ att- trpE+ trpC+

5) R+ P+ O- att+ trpE+ trpC- / R- P+ O+ att+ trpE- trpC+

6) R+ P- O+ att+ trpE+ trpC- / R- P+ O+ att+ trpE- trpC+

7) R+ P+ O- att- trpE+ trpC- / R- P+ O- att+ trpE- trpC+

- 1. 2. 3. 4. 5. 6. 7.

Trp = trpE (-), trpC (-); No Trp = trpE (+), trpC (+)


- 1. 2. 3. 4. 5. 6. 7.

Trp = trpE (-), trpC (-); No Trp = trpE (+), trpC (+)


- 1. 2. 3. 4. 5. 6. 7.

Trp = trpE (-), trpC (-); No Trp = trpE (-), trpC (-)


- 1. 2. 3. 4. 5. 6. 7.

Trp = trpE (-), trpC (-); No Trp = trpE (-), trpC (+)


- 1. 2. 3. 4. 5. 6. 7.

Trp = trpE (+), trpC (-); No Trp = trpE (+), trpC (+)


- 1. 2. 3. 4. 5. 6. 7.

Trp = trpE (+), trpC (+); No Trp = trpE (+), trpC (+)


- 1. 2. 3. 4. 5. 6. 7.

Trp = trpE (-), trpC (-); No Trp = trpE (+), trpC (+)

5.

 Please explain, I understand how todetermine the single and double cross progeny, but not sure whereto to from there.


The following genotypesare a result of a three-point cross between

Offspring

#

z z j j oo

690

z+ z j+j oo

6

z z j+j o+o

119

z+z jj o+o

45

z+z j joo

108

z z j+j oo

49

z z j j o+o

5

z z+ j j+ oo+

675

  1. What are thefrequencies of the parental and the recombinantgenotypes?

  1. Which genotypes arethe result of a double recombination?

z+ z j+j o+ o (6) and z zj j o+ o (5) (is this correct?)

  1. Generate a geneticmap for the three genes z, j, and o.

In an example of recessive epistasis the product H substance is needed to express the blood antigen. A mating of IB I O Hh X I A I O Hh should produce what ratio of blood types?

a.

1/4 AB, 1/8 A, 1/8 B, 1/2 O

b.

3/8 AB, 3/16 A, 3/16 B, 1/4 O

c.

3/16 AB, 3/8 A, 3/16 B, 1/4 O

d.

1/4 AB, 3/16 A, 3/16 B, 3/8 O

e.

3/16 AB, 3/16 A, 3/16 B, 7/16 O