ECON 3U03 Study Guide - Midterm Guide: Normal Distribution, Null Hypothesis, Test Statistic
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The following is sample information. Test the hypothesis that the treatment means are equal. Use the 0.05 significance level. |
Treatment 1 | Treatment 2 | Treatment 3 |
5 | 5 | 6 |
5 | 4 | 6 |
8 | 6 | 6 |
9 | 3 | 5 |
(b) | What is the decision rule? (Round your answer to 2 decimal places.) |
Reject H0 if the test statistic is greater than . |
(c&d) | Compute SST, SSE, and SS total and complete an ANOVA table. (Round SS, MS and F values to 3 decimal places.) |
Source | SS | df | MS | F |
Treatments |
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Error |
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Total |
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1 | Which of the following statements about Type I and Type II errors is correct | ||||||||
a | Type I: Reject a true alternative hypothesis. Type II: Do not reject a false alternative. | ||||||||
b | Type I: Reject a true null hypothesis. Type II: Do not reject a false null hypothesis. | ||||||||
c | Type I: Reject a false null hypothesis. Type II: Reject a true null hypothesis. | ||||||||
d | Type I: Do not reject a false null hypothesis. Type II: Reject a true null hypothesis. | ||||||||
2 | You are reading a report that contains a hypothesis test you are interested in. The writer of the report writes that the p-value for the test you are interested in is 0.0749, but does not tell you the value of the test statistic. From this information you can: | ||||||||
a | Not reject the hypothesis at a Probability of Type I error = .05, but reject the hypothesis at a Probability of Type I error = 0.10 | ||||||||
b | Reject the hypothesis at a Probability of Type I error = .05, and reject at a Probability of Type I error = 0.10 | ||||||||
c | Not reject the hypothesis at a Probability of Type I error = 0.05, and not reject at a Probability of Type I error = 0.10 | ||||||||
d | Reject the hypothesis at a Probability of Type I error = .05, but not reject at a Probability of Type I error = 0.10 | ||||||||
3 | The random sample below is obtained to test the following hypothesis about the population mean. | ||||||||
H?: ? ? | 1500 | ||||||||
H?: ? > | 1500 | ||||||||
620 | 1711 | 366 | 2528 | 2678 | 1661 | 442 | 725 | 1938 | |
409 | 330 | 2480 | 542 | 369 | 2124 | 549 | 2074 | 1665 | |
1873 | 873 | 2143 | 2061 | 1177 | 2509 | 1264 | 2397 | 1523 | |
1837 | 1958 | 1041 | 1639 | 2199 | 2232 | 387 | 2270 | 2136 | |
1111 | 1883 | 2612 | 2230 | 1597 | 1726 | 694 | 1990 | 1354 | |
2090 | 909 | 2128 | 1608 | 747 | 1121 | 2220 | 2390 | 2347 | |
1041 | 316 | 655 | 632 | 2064 | 1901 | 532 | 552 | 846 | |
2704 | 1410 | 2165 | 1065 | 937 | 1452 | 2539 | 410 | 656 | |
1169 | 527 | 809 | 2364 | 2350 | 2210 | 1459 | 2391 | 856 | |
2711 | 1985 | 2382 | 2289 | 1927 | 518 | 2177 | 437 | 1151 | |
2018 | 1580 | 607 | 2715 | 2188 | 1691 | 1394 | 2610 | 1186 | |
695 | 2428 | 2246 | 858 | 2036 | 1681 | 2449 | 1578 | 1971 | |
1846 | 1729 | 2389 | 1737 | 1913 | 1863 | 2072 | 2593 | 2287 | |
2220 | 2230 | 551 | 458 | 2626 | 2731 | 488 | 2551 | 1736 | |
1373 | 307 | 1803 | 2647 | 2679 | 1508 | 1468 | 1443 | 516 | |
1002 | 2116 | 2616 | 817 | 2522 | 460 | 1879 | 1999 | 1837 | |
The level of significance of the test is ? = 0.05. Compute the relevant test statistic. | |||||||||
This is a(n) _______ (two-tail, upper-tail, lower-tail) test. The test statistic is TS = _______. | |||||||||
a | Two-tail test | TS = | 1.81 | ||||||
Do not reject H?: ? ? 1500. Conclude that the population mean is not greater than 1500. | |||||||||
b | Upper tail test. | TS = | 1.52 | ||||||
Do not reject H?: ? ? 1500. Conclude that the population mean is not greater than 1500. | |||||||||
c | Upper tail test. | TS = | 1.81 | ||||||
Reject H?: ? ? 1500. Conclude that the population mean is greater than 1500. | |||||||||
d | Lower tail test. | TS = | 1.98 | ||||||
Do not reject H?: ? ? 1500. Conclude that the population mean is no greater than 1500. | |||||||||
4 | Consider the following hypothesis test. | ||||||||
H?: ? ? | 30 | ||||||||
H?: ? > | 30 | ||||||||
A random sample of n = 15 yielded the following observations | |||||||||
51 | 38 | 26 | 16 | 28 | |||||
57 | 20 | 33 | 35 | 23 | |||||
21 | 47 | 56 | 54 | 36 | |||||
Use ? = | 0.05 | ||||||||
TS = ______ | CV = ______ | State the decision rule. | |||||||
a | 1.68 | 1.761 | Do not reject H?. Conclude the mean is not greater than 30. | ||||||
b | 1.68 | 1.64 | Reject H?. Conclude the mean is greater than 30. | ||||||
c | 1.847 | 2.145 | Do not reject H?. Conclude the mean is not less than 30. | ||||||
d | 1.847 | 1.761 | Reject H?. Conclude the mean is less than 30. | ||||||
5 | In a recent study, a major fast food restaurant had a mean service time of 165 seconds. The company embarks on a quality improvement effort to reduce the service time and has developed improvements to the service process. The new process will be tested in a sample of stores. The new process will be adopted in all of its stores, if it reduced mean service time by more than 45 seconds compared to the current mean service time. To perform the hypothesis test, the sample of 48 stores yields the following data (seconds). | ||||||||
90 | 96 | 133 | 108 | 136 | 110 | 119 | 138 | ||
129 | 98 | 101 | 92 | 135 | 124 | 115 | 90 | ||
132 | 125 | 110 | 124 | 126 | 138 | 94 | 130 | ||
108 | 96 | 140 | 135 | 102 | 114 | 109 | 137 | ||
138 | 104 | 108 | 134 | 92 | 107 | 96 | 119 | ||
105 | 111 | 96 | 136 | 126 | 116 | 98 | 131 | ||
Use ? = | 0.05 | ||||||||
|TS| = ______ | |CV| = ______ | ||||||||
a | 1.548 | 1.678 | Do not reject H?. The mean service time is not reduced by more than 45 seconds. Do not adopt the new process. | ||||||
b | 1.871 | 1.678 | Reject H?. The mean service time is reduced by more than 45 seconds. Adopt the new process. | ||||||
c | 1.871 | 1.640 | Do not reject H?. The mean service time is not reduced by more than 45 seconds. Do not adopt the new process. | ||||||
d | 1.548 | 1.640 | Reject H?. The mean service time is reduced by more than 45 seconds. Adopt the new process. | ||||||
An advertising agency wants to know if the magazine they advertise in makes a difference in the response to the magazine readers. Each reader was asked to give the advertisement a rank between 0 and 10 (0 for no interest to 10 with high interest). They then survey 10 people that read one of the three different magazines that the company was interested in advertising in. The response of those ten people are:
Sports Illustrated | Home and Garden | In Magazine |
5 | 5 | 8 |
4 | 7 | 8 |
7 | 3 | 5 |
8 |
At a significance level of .05 can we conclude that the mean rank for the advertisement is the same for all three of the magazines?
What is your null hypothesis?
What is your alternative hypothesis?
What is the value of the SST?
What is the value of the SSE
What is the total
What are the degrees of freedom for the treatments?
What are the degrees of freedom for the error?
What is the MST
What is the MSE
What is the calculated F Distribution?
What is the critical value of the F statistic?
What is your decision?
Interpret your results