Textbook ExpertVerified Tutor
8 Nov 2021
Given information
Here, the mean of the given distribution (μx)=$44,000; The standard deviation (σx)=6,500;
the sample size(n)=10; Let X=$400,000;
P(∑X>$400,000)=?
Step-by-step explanation
Step 1.
As we know, the mean for the total salaries of the teachers =(n)*(μx)=10*($44,000)=$440,000;
And the standard deviation for the total salaries of the teachers ;
;
Now by the z-score formula,
Z=(400,000-440,000)/20,554.80=-1.9460;
So, NORM.S.DIST(-1.9460)=0.02582;
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