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22 Oct 2021
Given information
Researcher A: 3; 4; 11; 15; 16; 17; 22; 44; 37; 16; 14; 24; 25; 15; 26; 27; 33; 29; 3; 44; 13; 21; 22; 10; 12; 8; 40; 32; 26;
27; 31; 34; 29; 17; 8; 24; 18; 47; 33; 34
Frequency is the number of time the data occurs.Here the Data of 40 AIDS patients representing interval of 6 in each row so we have to find frequency by Tally method
Researcher A Table
Tally method of Frequency=total number lies in that interval
here 3, 4 survival patient lies between 0.5-6.5 interval so it frequency becomes 2, there are 5 NO. of survival lies between 6.5-12.5 so its frequency will become 5
Survival length(in months) | No. of survival(tally method) | Frequency |
0.5-6.5 | || | 2 |
6.5-12.5 | |||| | 5 |
15.5-18.5 | |||| |||| | 10 |
18.5-24.5 | |||| | 4 |
24.5-30.5 | |||| || | 7 |
30.5-36.5 | |||| || | 7 |
36.5-42.5 | || | 2 |
42.5-48.5 | ||| | 3 |
Total=40 |
Step-by-step explanation
Step 1.
For Relative Frequency
Relative Frequency is the fraction of frequency of that class to the total frequency
Relative Frequency=Frequency of the Class/Total frequency
Survival length(in months) | Frequency | Relative Frequency |
0.5-6.5 | 2 | 2/40=0.05 |
6.5-12.5 | 5 | 5/40=0.125 |
12.5-18.5 | 10 | 10/40=0.25 |
18.5-24.5 | 4 | 4/40=0.1 |
24.5-30.5 | 7 | 7/40=0.175 |
30.5-36.5 | 7 | 7/40=0.175 |
36.5-42.5 | 2 | 2/40=0.05 |
42.5-48.5 | 3 | 3/40=0.075 |
Total=40 |
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