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10.58 (20 pts) Refer to the American Heart Association Conference (November 2005) study to gauge whether animal-assisted therapy can improve the physio- logical responses of heart failure patients, presented in Exercise 10.38 (above). You found evidence of a difference among the treatment means for the three treatments: Group T (volunteer plus trained dogs), Group Y (volunteer only), and Group C (control). Conduct a Bonferroni analysis to rank the three treat- ment means. Use an experiment-wise error rate of a = 0.03. Interpret the results for the researchers. Hint: You may use the fact that the Bonferroni formula for a confidence interval for the difference Hi - W; is Ti – ī; £ta-/2(s)1/n; +1/nj, where a* = 2a/{k(k – 1)} is the experiment-wise error rate, and k is the total number of treatment means compared. 10.38 [20 pts) In a study to gauge whether animal-assisted therapy can improve the physiological response of heart failure patients (American Heart Association Conference, November 2005), a team of nurses from the UCLA Medical Center randomly divided 76 heart patients into three groups. Each patient in Group T was visited by a human volunteer accompanied by a trained dog, each patient in group V was visited by a volunteer only, and the patients in Group C were not visited at all. The anxiety level of each patient was measured (in points) both before and after the visits. The accompanying table gives summary statistics for the drop in anxiety level for patients in the three groups. Sample Mean Standard Size Drop Deviation Group T: Volunteer + Trained Dog 10.5 7.6 Group V: Volunteer only 25 3.9 7.5 Group C: Control group (no visit) 25 1.4 26 7.5 The mean drops in anxiety levels of the three groups of patients were com- pared with the use of the analysis of variance. Although the ANOVA table was not provided in the article, sufficient information is given to reconstruct it. (a) [3 pts) Compute SST for the ANOVA, using the formula SST = {:(*– )”, where ī is the overall mean drop in anxiety level of all 76 subjects. (b) [3 pts) Recall that SEE for the ANOVA can be written as SSE = (n1 – 1)sî + (n2 – 1)sź +(n3 – 1) sĩ, where s , s, and s are the sample variances associated with the three treatments. Compute SSE for the ANOVA. (c) [7 pts. Use the results from parts (a) and (b) to construct the ANOVA table. (d) (4 pts) Is there sufficient evidence (at level a = 0.01) of differences among the mean drops in anxiety levels by the patients in the three groups? (e) [3 pts Comment on the validity of the ANOVA assumptions. How might this affect the results of the study?

Problem Set 2: The One-way ANOVA Research Scenario: A group of clinical psychologists conducts a randomized clinical trial examining paychosocial and pharmaceutical treatments, alone or in combination for Social Anxiety Disorder (SAD). Participants who have been diagnosed with SAD are randomly assigned to one of three treatment groups (n = 9 each): cognitive behavioral therapy (CBT). Paxil (a common SSRI prescribed to patients with SAD); and CBT + Paxil. The participants are assessed after 6 months of treatment using the Social Avoidance and Distress Scale (SADS; Watson and Friend, 1969), where higher scores indicate higher levels of social anxiety. Is there a difference in the effects of these three treatments on social anxiety outcomes? Using this table, enter the data into a new SPSS data file and run a one-way ANOVA to test whether there is a difference in social anxiety levels (as measured by the SADS) among the three groups. Create a boxplot to show the difference in SADS scores among the three groups CBT Pavil® CBT + Paxil 1. Paste SPSS output. pts) 2. Write an APA-style Results section based on your analysis. Include your boxplot as an APA-style figure as demonstrated in the APA writing presentation. (Results - 8 pts; Graph = pts) The One-way ANOVA Template Template: Results A one-way ANOVA was conducted to determine the effect of [Independent Variable (Level 1, Level 2, Level 3, ... for as many levels as there are] on [Dependent Variable). Figure 1 illustrates the [DV) across [levels of the IV). The results indicate a significant/not significant effect, [F(df twen, dfihin) = ##, p = ##, partial eta squared - ##]. (Include this next section only if results of ANOVA are significant: Post hoc tests were conducted using Tukey's HSD test. The comparisons revealed a significant difference between [Group X] (M = ##, SD = ##) and [Group Y] (M = ##, SD = ##), p = ##... etc. for each significant difference found.) We therefore reject/fail to reject] the null hypothesis that the different levels of the Independent Variable] have the same effect on the [Dependent Variable]. (Any more conclusions based on significant results can go here.)

5. A researcher is interested in studying the effect that the amount of fat in the diet and amount of exercise has on the mental acuity of middle-aged women. The researcher used three different treatment levels for the diet and two levels for the exercise. The results of the acuity test for the subjects in the different treatment levels are shown below. Diet <30% fat 30% - 60% >60% fat fat Exercise <60 minutes + + 60 minutes or more 00 00 + 00 + in a Perform a Two-way analysis of variance (ANOVA) and report the results using CUOLE APA style, report whether significance was found for Factor A Factor B. and/or an interaction between Factors A and B was found b. If the test statistic is significant, run a post hoc test to determine between what groups significance was found c. Report an effect size for all significant results

5. A researcher is interested in studying the effect that the amount of fat in the diet and amount of exercise has on the mental acuity of middle-aged women. The researcher used three different treatment levels for the diet and two levels for the exercise. The results of the acuity test for the subjects in the different treatment levels are shown below. Diet <30% fat 30% - 60% >60% fat fat Exercise <60 minutes + + 60 minutes or more 00 00 + 00 + in a Perform a Two-way analysis of variance (ANOVA) and report the results using CUOLE APA style, report whether significance was found for Factor A Factor B. and/or an interaction between Factors A and B was found b. If the test statistic is significant, run a post hoc test to determine between what groups significance was found c. Report an effect size for all significant results

Consider the accompanying data collected for a two-way ANOVA. 23Click the icon to view the data table. a) Using a = 0.025, is there significant interaction between Factors A and B? b) Using a = 0.025, are the Factor A means different? c) Using a = 0.025, are the Factor B means different? Factor A Level 1 Level 2 Level 3 Factor B Level 1 29 a) Using a = 0.025, is there significant interaction between Factors A and B? - 22 31 34 35 Level 2 Identify the hypotheses for the interaction between Factors A and B. Choose the correct answer below. 24 28 - 34 23 O A. Ho: Factor A and B do interact, Hy: Factor A and B do not interact Print Done O B. Ho: HA* H3, H4: HA = HB C. Ho: MA = H8, H1: HA* MB O D. Ho: Factor A and B do not interact, Hy: Factor A and B do interact Consider the accompanying data collected for a two-way ANOVA. Click the icon to view the data table. a) Using a = 0.01, is there significant interaction between Factors A and B? b) Using a = 0.01, are the Factor A means different? c) Using a = 0.01, are the Factor B means different? a) Using a = 0.01, is there significant interaction between Factors A and B? Identify the hypotheses for the interaction between Factors A and B. Choose the correct answer below. A Ho: Factor A and B do not interact, Hy: Factor A and B do interact B. Ho: Factor A and B do interact, Hy: Factor A and B do not interact OC. Ho: MA=H8, H1: HATHB OD. HO: HATHB, HE HA FHB Find the p-value for the interaction between Factors A and B. p-value = 0.947 (Round to three decimal places as needed.) Draw the appropriate conclusion for the interaction between Factors A and B. Choose the correct answer below. O A. Do not reject the null hypothesis. There is insufficient evidence to conclude that the means differ. OB. Reject the null hypothesis. There is sufficient evidence to conclude that Factors A and B interact. C. Reject the null hypothesis. There is insufficient evidence to conclude that the means differ. D. Do not reject the null hypothesis. There is insufficient evidence to conclude that Factors A and B interact. b) Using a = 0.01, are the Factor A means different? Identify the hypotheses to test for Factor A. Choose the correct answer below. ZA HO: HATHB. H: HA #HB OB. Ho: A1 = HA2 = HA3, H: HA1 > HA2>HA3 OC. Ho: MA1 MA2 MA3, H4: HA1 = HA2 =HA3 D. H um=unn = 19. H.: Not all Factor A means are equal Find the p-value for Factor A. p-value = 0.012 (Round to three decimal places as needed.) Draw the appropriate conclusion for Factor A. Choose the correct answer below. O A Reject the null hypothesis. There is insufficient evidence to conclude that the means differ. OB. Reject the null hypothesis. There is sufficient evidence to conclude that not all Factor A means are equal. C. Do not reject the null hypothesis. There is insufficient evidence to conclude that not all Factor A means are equal. O D. It is inappropriate to draw a conclusion from this test because the Factors A and B interact. c) Using a = 0.01, are the Factor B means different? Identify the hypotheses to test for Factor B. Choose the correct answer below. O A. Ho: 481 * HB2, HT: 181 = HB2 OB. Ho: HB1 = HB2 = HB3, Hy: Not all Factor B means are equal OC. HO HA =H3, H4: HATHB ID. Ho: PB1 = PB2, Hy: Not all Factor B means are equal Find the p-value for Factor B. p-value = 0.763 (Round to three decimal places as needed.) Draw the appropriate conclusion for Factor B. Choose the correct answer below. O A Reject the null hypothesis. There is sufficient evidence to conclude that not all Factor B means are equal. B. Reject the null hypothesis. There is insufficient evidence to conclude that the means differ. C. Do not reject the null hypothesis. There is insufficient evidence to conclude that not all Factor B means are equal.

From candy to jewelry to flowers, the average consumer was expected to spend $104.91 for Mother's Day in 2005, according to the Democrat & Chronicle article 'Mom's getting more this year' (May 7, 2005). Local merchants thought this average was too high for their area. They contracted an agency to conduct a study. A random sample of 58 consumers was taken at a local shopping mall the Saturday before Mother's Day and produced a sample mean amount of $94.83. If o = $29.5, does the sample provide sufficient evidence to support the merchants' claim at the .05 significance level? (a) Find z. (Give your answer correct to two decimal places.) (ii) Find the p-value. (Give your answer correct to four decimal places.) (b) State the appropriate conclusion. Reject the null hypothesis, there is not significant evidence to support the merchants' claim. Reject the null hypothesis, there is significant evidence to support the merchants' claim. Fail to reject the null hypothesis, there is significant evidence to support the merchants' claim. o Fail to reject the null hypothesis, there is not significant evidence to support the merchants' claim. You may need to use the appropriate table in Appendix B to answer this question.

An engineer has designed a valve that will regulate water pressure on an automobile engine. The valve was tested on 270 engines and the mean pressure was 6.5 pounds/square inch (psi). Assume the population variance is 0.36. If the valve was designed to produce a mean pressure of 6.6 psi is there sufficient evidence at the 0.02 level that the valve performs below the specifications? Step 4 of 6: Find the P-value of the test statistic. Round your answer to four decimal places. AnswerHow to Enter) 2 Points Keypad

A sample of 1200 computer chips revealed that 72% of the chips fail in the first 1000 hours of their use. The company's promotional literature claimed that below 75% fail in the first 1000 hours of their use. Is there sufficient evidence at the 0.02 level to support the company's claim? State the null and alternative hypotheses for the above scenario.

Question 9 of 18, Step 1 of 1 5/1 Correct An engineer has designed a valve that will regulate water pressure on an automobile engine. The valve was tested on 120 engines and the mean pressure was 4.1 Ibs/square inch. Assume the variance is known to be 0.81. If the valve was designed to produce a mean pressure of 4.3 lbs/square inch, is there sufficient evidence at the 0.1 level that the valve performs below the specifications? State the null and alternative hypotheses for the above scenario. Tables Keypad Answer Submit Answer 2020 Mawkes Learning to search

O Save & End Certify Lesson: 10.1 Fundamentals of Hypothesis . LADARIUS WIGGINS Question 11 of 18, Step 1 of 1 6/18 Correct A newsletter publisher believes that less than 48 % of their readers own a Rolls Royce. Is there sufficient evidence at the 0.0O1 level to substantiate the publisher's claim? State the null and alternative hypotheses for the above scenario. Answer E Tables Keypad Ho: Н. Submit Answer O 2020 Hawkes Learning here to search

 

program and see what happens so please enter your message so we get this message now. What we want to do is display this message for as long as the user remains in our program. So we use the while loop so we type while True which means while the condition is True. So In this case the condition is that our message variable is not empty and that 's why we put a comma after while because that 's what tells Python to keep looping while this condition is met okay now if you type exit out of our program right now you will get an error message because our while loop condition is not met Okay. So now let's add a counter to our program. So we can keep track of how many times our while loop condition has been met. So we add a variable called counter and set it to 1. Now if you run our program again and type exit out. of it, you will see that our while loop condition has been met four times. Now Let's add another counter and set it to 2 now. If you run our program again and type exit out of it. You will see that our while loop condition has been met six times now let's add another counter and set it to 3. Now If you run our program again and type exit out of it, you will see that our while loop condition has been met nine times now finally let's add another counter and set it to 4. Now. If you run our program again and type exit out of it. You will see that our while loop condition has been met 12 times. So this is how we can use the while loop in Python to write a value to the user. So next time I 'll show you how to read values from the user and how to write values to the user. THe passage discusses how an error occurred in a program. THe error was caused by attempting to subtract a string from an integer, which Python does not support. TO solve the problem, the author converted the string to an integer and solved the problem.. function is the string that we got from the input function now let's run the program so 10 and 20.1 and here 's the result In. This passage, the author explains how to solve a problem in Python where two numbers are being combined together as strings.. THe first number is read into a variable, and the second number is read into a second variable.. THe sum of the two numbers is then calculated using the float function, which converts both numbers to their. numeric representations. Finally, the sum of the two numbers is displayed on the terminal. One way to solve This problem would be to use the int function, which would convert both numbers to integers. However,. Since we're dealing with strings, we need to use the float function instead. Additionally,. Since we're not required to use the float function, we could have just called it at the time. We wanted to calculate the sum of the two numbers. IN conclusion,. This passage provides some insights into how to solve a problem in Python where two numbers are being combined together as strings.. The first step is to read in the first number into a variable, and the second step is to read in the second number.. The sum of the two numbers is then calculated using the float function, which converts both numbers to their numeric representations.. Finally, the sum of the two numbers is displayed on the terminal..