adeori
Lovely Professional University - LPU
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adeoriLv1
24 Jan 2023
frequency table for the data using the class ranges you provided: Class Freque...
adeoriLv1
24 Jan 2023
e. The outcome of testing Jane's null hypothesis cannot be determined from the...
adeoriLv1
24 Jan 2023
Question 4. a. gets smaller In order to reject a null hypothesis, one should g...
adeoriLv1
24 Jan 2023
Answer: The Arithmetic Mean (AM) of a set of numbers is the sum of all the num...
adeoriLv1
24 Jan 2023
I'm sorry, but I am unable to accurately determine the distance "y" to the cen...
adeoriLv1
24 Jan 2023
Answer: a) To find the average energy leakage in joules per second, we can use...
adeoriLv1
24 Jan 2023
Completeness is a concept in theoretical computer science that refers to the a...
adeoriLv1
24 Jan 2023
Answer: New Mexico has a rich history of cultural conflict and exchange, datin...
A power plant burns coal and generates an average of660.0Megawatts (MW) of electrical power while discharging 990.00MW aswaste heat. Find the total electrical energy generated by theplantin a 30-day period. Coals vary a lot intheir energy content.The energy released by the burning of coal istypically between 23and 33 Mega Joules per kg of coal. The powerplant above uses coalrated at 25.3 MJ/kg to heat the boilers. Someof that heat isconverted to electrical energy, but most is wasteheat dischargedinto the environment. Assume that it takes about2.26 kg of oxygento burn 1 kg of coal (The actual amount varieswith the type coal).Find the total mass of the reagents used inoperating for 30days.
The total average power (electrical + heat), and the time,givesthe total energy. Since you know the energy per kilogram ofcoal,and how many kg of oxygen are required for each kg of coal,you canget the total reagent mass. |
adeoriLv1
24 Jan 2023
Step-by-step explanation: To find the total electrical energy generated by the...
adeoriLv1
24 Jan 2023
Answer: It is certainly possible to convert wasted heat into useful work, ener...
adeoriLv1
24 Jan 2023
Step-by-step explanation: To locate the centroid of the shaded area, we would ...