shubhamsoniss1998

shubhamsoniss1998

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Shubham Soni

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The Base Hydrolysis
of Ethyl Acetate

The reaction of ethyl acetate and hydroxide ions yields ethanol and acetate ions, as shown below.

CH3COOC2H5 (aq) + OH– (aq) → CH3CH2OH (aq) + CH3COO– (aq)

The progress of this reaction can be observed by monitoring the conductivity of the reaction mixture. Although the reactants and products each contain an ion, the OH– ion has a higher ionic mobility than the CH3COO– ion. This results in a net decrease in the conductivity of the reaction mixture as the reaction proceeds.

Ethyl acetate is the major active ingredient in commercial acetone-free, nail-polish removers. The molar concentration of CH3COOC2H5 in this product is 0.10 M. You can successfully use one of these over-the-counter products in this experiment. The primary objective of this experiment is to conduct a series of reactions from which you will determine the rate law expression for the base hydrolysis of ethyl acetate.

OBJECTIVES

In this experiment, you will

Conduct the base hydrolysis of ethyl acetate under various conditions.

Calculate the rate law constant, k, for the reaction.

Determine the rate law expression for the reaction.

Figure 1

MATERIALS

Vernier computer interface

0.010 M sodium hydroxide, NaOH, solution

computer

0.10 M ethyl acetate, CH3COOC2H5, solution

Vernier Conductivity Probe

distilled water

Vernier Stir Station

10 mL graduated cylinder

or magnetic stirrer and ring stand

two 50 mL graduated cylinders

stirring bar or Microstirrer

250 mL beaker

utility clamp

two 100 mL beakers

PROCEDURE

1. Obtain and wear goggles.

2. Connect a Conductivity Probe to Channel 1 of the Vernier computer interface. Connect the interface to the computer using the proper cable.

3. Set the toggle switch on the Conductivity Probe to the 0–2000 μS/cm range.

4. Start the Logger Pro program on your computer. Open the file “29 Ethyl Acetate” from the Advanced Chemistry with Vernier folder.

5. Obtain the materials you will need to conduct this experiment.

Two 50 mL graduated cylinders

One 10 mL graduated cylinder

100 mL beaker in which to conduct the reaction

Approximately 90–100 mL of 0.010 M NaOH solution in a 250 mL beaker

Approximately 10 mL of 0.10 M CH3COOC2H5 solution in a second 100 mL beaker

Distilled water (75-80 mL)

6. During the experiment you will conduct three trials. This step describes the process for conducting Trial 1. When you repeat this process, use the correct volumes for each trial based on the table below.

Trial

NaOH (mL)

CH3COOC2H5 (mL)

H2O (mL)

1

20.0

2.0

28.0

2

40.0

2.0

8.0

3

20.0

4.0

26.0

Use a utility clamp to connect the Conductivity Probe to the post of a Stir Station or a ring stand as shown in Figure 1.

Measure 20.0 mL of NaOH solution and 28.0 mL of distilled water into a 100 mL beaker. Carefully place a stirring bar in the beaker of solution. Place the beaker on the platform of the Stir Station, or on the magnetic stirrer.

Position the Conductivity Probe in the 100 mL beaker so that the opening near the tip of the probe is completely immersed in the solution and the stirring bar will not strike the probe. Record the initial conductivity of the NaOH solution in your data table, but do not start the data collection.

Turn on the Stir Station to setting 5 or 6 (moderate stirring, small vortex).

Measure out 2.0 mL of CH3COOC2H5 solution.

Click to begin data collection. Add the 2.0 mL of CH3COOC2H5 solution to the beaker of NaOH solution. Data will be collected for five minutes.

7. When the data collection is complete, dispose of the contents of the beaker as directed. Rinse and clean the beaker and the Conductivity Probe for the second trial.

8. Examine the graph of your data. The graph will show a gradual, nonlinear, conductivity decrease. Click and drag the cursor across a linear section of the graph over 20–30 s during the first minute. Click on the Linear Regression button, , to calculate the best-fit line equation. Record the slope, in your data table, as the initial rate of the Trial 1.

9. Repeat Steps 6–8 to conduct Trials 2 and 3.

DATA TABLE

Trial

[NaOH]

[CH3COOC2H5]

Initial conductivity
of NaOH solution
(μS/cm)

Initial rate (μS/cm)/s)

1

0.1

0.1

1035

-4.2

2

0.1

0.1

2112

-5.8

3

0.1

0.1

1259

-6.7

4

0.1

0.2

1236

-1.6

5

0.1

0.2

2390

-1.8

6

0.1

0.2

1302

-0.8

DATA ANALYSIS

1. What is the order of the reaction in sodium hydroxide and ethyl acetate? Explain how you determined order for each reactant.

2. Write the rate law expression for the reaction.

3. Convert conductivity to molar concentration by using the initial conductivity of the NaOH solution as a conversion factor. Convert each initial rate into the units: moles/L/s. For example, if the initial conductivity of the NaOH solution was 2000 μS/cm and initial rate was 5.0 μS /cm/s, you would convert the rate to moles/L/s by completing the following calculation: Rate = 5.0 μS/cm/s ´ [(0.005 mol/L)/(2000 μS/cm)] = 1.25 ´ 10–5 mol/L/s. Use these new values to calculate the rate constant, k.

Answer: 1. The order of the reaction in sodium hydroxide is first order, and t...

Can you solve the last four questions?

Answer: Greater. The result indicates that the product solution has a higher c...

Can you solve the last questions?

Answer:The result can be explained by the fact that the conductivity of the re...

1. Concentrations of acetic acid and sodium acetate in the prepared buffer solutions in Part I as noted in the table in the lab handout

The acetic acid and sodium acetate solutions will have concentrations of 0.50 M.

2. Theoretical pH of prepared buffer solutions in Part I

There are 0.10 M aqueous solutions of HCl and NaOH available in the lab for this part of the experiment.

3. Theoretical pH of solutions and deionized water after the addition of strong acid and strong base in Part II of the experiment.

Measure 20 mL of buffer solution A using a graduated cylinder and pour the solution into a clean beaker labeled A1. Measure 20 mL of buffer solution B using a clean graduated cylinder and pour the solution into a clean beaker labeled B1. Measure 20 mL of the deionized water sample from part I and pour the solution into a clean beaker labeled W1.

3. Using a clean graduated cylinder, add 10 mL of 0.10 M HCl (aq) to each solution A1, B1 and W1. Mix the solutions well using a glass stir rod making sure to rinse the stir rod in between mixing each solution. Measure and record the pH of all 3 solutions in your notebook.

4. Measure 20 mL of buffer solution A using a graduated cylinder and pour the solution into a clean beaker labeled A2. Measure 20 mL of buffer solution C using a clean graduated cylinder and pour the solution into a clean beaker labeled C2. Measure 20 mL of the deionized water sample from part I and pour the solution into a clean beaker labeled W2.

5. Using a clean graduated cylinder, add 10 mL of 0.10 M NaOH (aq) to each solution A2, C2 and W2. Mix the solutions well using a glass stir rod making sure to rinse the stir rod in between mixing each solution. Measure and record the pH of all 3 solutions in your notebook.

Answer: A 0.50 0.50 4.76 4.76B 0.50 0.50 4.76 4.76C 0.50 0.50 4.76 4.76The the...
Answer: The buffering effect will fail when the total amount of 6 M hydrochlor...
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Please answer the following questions regarding the nature of buffers:

Part 1: A few drops of 1.0 M HCl are added to pure water and to a buffered solution containing hydrogen phosphate (HPO42-) and dihydrogen phosphate (H2PO4-). You observed that the pH of the pure water drops significantly, while the pH of the buffered solution only decreases slightly. Which explains the result?

A) H2PO4- reacted with the HCl, changing to HPO42- and removing H+ from solution

B) HPO42- reacted with the HCl, changing to H2PO4- and removing H+ from solution

C) H2PO4- reacted with the HCl, changing to H3PO4 and removing H+ from solution

Part 2: A few drops of 1.0 M NaOHl are added to pure water and to a buffered solution containing hydrogen phosphate (HPO42-) and dihydrogen phosphate (H2PO4-). You observed that the pH of the pure water increases significantly, while the pH of the buffered solution only increases slightly. Which explains the result?

A) HPO42- reacted with the NaOH, changing to H2PO4- and removing OH- from solution

B) HPO42- reacted with the NaOH, changing to PO43- and removing OH- from solution

C) H2PO4- reacted with the NaOH, changing to HPO42- and removing OH- from solution

Part 3: You begin with 43 mL of the buffered solution. If the solution is 1.0 M H2PO4- and 0.5 M HPO42-, how many mL of the 1.0 M solution of HCl would be needed to 'overwhelm' and completely react with the buffer?

Part 4: You begin with 43 mL of the buffered solution. If the solution is 1.0 M H2PO4- and 0.5 M HPO42-, how many mL of the 1.0 M solution of NaOH would be needed to 'overwhelm' and completely react with the buffer?

Part 5: Buffers are solutions that can accept protons in the presence of a base and donate protons in the presence of an acid. Which of these would be able to function as a buffer?

A) Weak Acid + Weak Base

B) Weak Acid + Strong Acid

C) Weak Base + Strong Base

D) Strong Acid + Strong Base

Part 6: Buffers are defined as a solution containing one of the following:

1)A weak acid and that weak acid’s conjugate base

2)A weak base and that weak base’s conjugate acid Which of the following solutions would form a buffer? Select all that apply.

A) NH3 + NH4+

B) HF + F-

C) NH3 + NaOH

D) HF + HCl

E) OH- + H+

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