aquamarinealpaca591
Karol E.
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2 Jun 2021
(a) The correct answer is: No, The probability of drawing a specific second ca...
2 Jun 2021
Frequency table: AGE Frequency x xf x2 x2f 25-34 20.9 30 627 900 18810 35-44 3...
2 Jun 2021
Formula for Sample Variance: Solution: ANS: The Sample variance is 0.229 (Note...
2 Jun 2021
A.) Location Population (L) X Y L.X L.Y Smallville 2200 5.8 2.8 12760 6160 Big...
2 Jun 2021
A.) Decision tree Answer: There can be two options: You can undergo market res...
The breaking strengths of cables produced by a certain manufacturer have a standard deviation of 91 pounds. A random sample of 80 newly manufactured cables has a mean breaking strength of 1750 pounds. Based on this sample, find a 95%Ā confidence interval for the true mean breaking strength of all cables produced by this manufacturer. Then complete the table below.
Carry your intermediate computations to at least three decimal places. Round your answers to one decimal place.Ā
(If necessary, consult aĀ list of formulas.)
I need both the lower limit, and upper limit of the 90% confidence interval.
2 Jun 2021
Given: a.) 90% Solution: Ans: (1733.26 , 1766.74)
2 Jun 2021
Solution: Ans: x=38.32
2 Jun 2021
GIVEN: Hypothesis: Critical Value: , (Note: since we are using two tailed test...
2 Jun 2021
Solution: Let Ī² > Ī²0. Then f(x1, Ā· Ā· Ā· , xn|Ī²)/f(x1, Ā· Ā· Ā· , xn|Ī²0) = Āµ Ī² Ī²...
2 Jun 2021
Answer: Hypothesis
2 Jun 2021
Given: , , Hypothesis: Sample proportions: Pooled proportions: Critical Value:...
2 Jun 2021
a.) First we need to determine if the population mean of litter sizes differ a...
2 Jun 2021
Given: Physics Mathematics Ļ1=70 Ļ2=70 Hypothesis: H0: P1=P2 Ha: P1>P2 Form...
2 Jun 2021
Given: Ī¼=16 Ļ=0.4 n=16 xĢ=15.84 Ī±=0.10 1st step: Construct our hypothesis 2nd ...
2 Jun 2021
Parts of the Problem Answer 4x + 1y <= 480 minutes Constraint x = the # of ...
2 Jun 2021
1.) Experimental unit :40 customers Quantitative ( Waiting time) Variable (x):...
2 Jun 2021
Solution: In this case, in 45 year expected number of Class D 20 volcanic erup...
2 Jun 2021
(a) Population distribution of gender: Female distribution=0.61 (already given...
2 Jun 2021
Given: Solution: t-value at 91% confidence level, Formula to use in getting th...
2 Jun 2021
In this problem the expected value is 10, so we have to determine the probabil...
2 Jun 2021
Given: n_1=1795 (Student that doesn't cheat) n_2=840 (Student that cheated) To...
2 Jun 2021
Frequency table: AGE Frequency x xf x2 x2f 25-34 20.9 30 627 900 18810 35-44 3...
2 Jun 2021
(a) Population distribution of gender: Female distribution=0.61 (already given...
2 Jun 2021
GIVEN: ALASKA NEW YORK Where, FORMULA: Since we have to compare the confidence...
2 Jun 2021
ANSWER: The two-sample proportion z-test is the appropriate test here. The hyp...
2 Jun 2021
Since n=4; therefore from the table, the critical value of correlation coeffic...
2 Jun 2021
The answer is option D. Explanation: The standard deviation measure the disper...
2 Jun 2021
Given: Solution: A.) Utilization is the ration between arrival rate and servic...
2 Jun 2021
a.) State the Null and Alternative hypothesis Ans: b.) State wether to use a l...
2 Jun 2021
Given: Āµ = 59 sd= 4.8 Solution: Empirical rules predicts that 95% within tthe ...
2 Jun 2021
For the top percentile, z=1.28 Therefore, the value is equal to the mean = z*s...
2 Jun 2021
The correct answer is : Option 1: Each experimental subject in a placebo-contr...
2 Jun 2021
Formula: therefore the probability that atleast 60 are currently being repaire...
2 Jun 2021
Frequency table: AGE Frequency x xf x2 x2f 25-34 20.9 30 627 900 18810 35-44 3...
2 Jun 2021
Given: Step 1: Set the hypothesis (Based on the hypothesis given, we can say t...
2 Jun 2021
1. Since the population standard deviation is known and the distribution is no...
2 Jun 2021
(a) Construct a histogram First, we have to determine the number of class inte...
2 Jun 2021
Raw score of cutoff for 10% of scores. Answer: 26.4
2 Jun 2021
a.) State the null and alternative hypothesis: b.) Check whether np0(1-p0) is ...
2 Jun 2021
Given: N=226 P= 182/226 =0.80531 In this problem we can use standard normal z ...